python抓取google搜索url

import sysurl = ('https://ajax.googleapis.com/ajax/services/search/web''?v=1.0&q=%s&rsz=8&start=%s') % (search,page)try:    request = urllib2.Request(    url, None, {'Referer': 'http://www.baidu.com'})    response = urllib2.urlopen(request)            # Process the JSON string.    results = simplejson.load(response)    info = results['responseData']['results']except Exception,e:    print e    time.sleep(5)    continue                for minfo in info:        for key in minfo.keys():            if key == 'url':                 try:                     print 'url:%s' % minfo[key]