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能不能帮小弟我看看这段代码出错在哪?

发布时间: 2012-09-08 10:48:07 作者: rapoo

能不能帮我看看这段代码出错在哪?谢过!!!!!!!!!!
第一个这个是正常显示的...先贴出代码

PHP code
<form name="form1" method="get" action="search.php">  <label for="title"></label>  <div align="center">    标题      <input type="text" name="title" id="title">    <input type="submit" name="submit" id="button" value="搜索">  </div></form><div align="center">  <?php header("Content-Type:text/html;charset=utf-8");include("conn.php");$biaoti=$_GET['title'];$biaoti2="%".$biaoti."%";$sql="select * from news where title like '$biaoti2'";$result=mysql_query($sql,$mylink);$result2=mysql_fetch_array($result);$i=0;echo "搜索内容:".$biaoti;echo "</br>";echo "搜索结果总数:".$i;if($biaoti==""){    echo "模块初始化已完成";        }    else    {?>  <table width="1079" height="102" border="1">    <tr>      <th width="81" height="45" bgcolor="#E2F4F6" scope="col">序号</th>      <th width="122" bgcolor="#E2F4F6" scope="col">发布所用账号</th>      <th width="346" bgcolor="#E2F4F6" scope="col">标题</th>      <th width="192" bgcolor="#E2F4F6" scope="col">时间</th>      <th width="144" bgcolor="#E2F4F6" scope="col">昵称</th>      <th width="77" bgcolor="#E2F4F6" scope="col">评论数</th>      <th width="71" bgcolor="#E2F4F6" scope="col">删除</th>    </tr><?php do{?>    <tr>      <th height="49" scope="col"><?php echo $commentcount=$result2['id'];?></th>      <th scope="col"><?php echo $result2['zhanghao'];?></th>      <th scope="col"><a href="view.php?id=<?php echo $result2['id'];?>">      <?php echo $result2['title'];?> </a></th>      <th scope="col"><?php echo date("Y-m-d H:i:s",strtotime($result2['time']));?></th>      <th scope="col"><?php echo $result2['name'];?></th>      <th scope="col"> <?php $sql2="select count(*) as abc from tbcomment where id='$commentcount'";    $sqlquery=mysql_query($sql2,$mylink);    $result4=mysql_fetch_array($sqlquery);    echo $result4['abc'];     ?></th>      <th scope="col"><a href="shanchu.php?id=<?php echo $result2['id'];?>"><?php echo "删除";?></a></th>    </tr><?php }while($result2=mysql_fetch_array($result))?>  </table></div><?php }?>


但我在22行加上一个do {}while()想统计搜索结果总数的时候.....表格中的搜索结果内容就显示不正常了...但搜索结果总数还是显示正常
贴上错误的代码
PHP code
<form name="form1" method="get" action="search.php">  <label for="title"></label>  <div align="center">    标题      <input type="text" name="title" id="title">    <input type="submit" name="submit" id="button" value="搜索">  </div></form><div align="center">  <?php header("Content-Type:text/html;charset=utf-8");include("conn.php");$biaoti=$_GET['title'];$biaoti2="%".$biaoti."%";$sql="select * from news where title like '$biaoti2'";$result=mysql_query($sql,$mylink);$result2=mysql_fetch_array($result);$i=0;do{$i++;}while($result2=mysql_fetch_array($result));echo "搜索内容:".$biaoti;echo "</br>";echo "搜索结果总数:".$i;if($biaoti==""){    echo "模块初始化已完成";        }    else    {?>  <table width="1079" height="102" border="1">    <tr>      <th width="81" height="45" bgcolor="#E2F4F6" scope="col">序号</th>      <th width="122" bgcolor="#E2F4F6" scope="col">发布所用账号</th>      <th width="346" bgcolor="#E2F4F6" scope="col">标题</th>      <th width="192" bgcolor="#E2F4F6" scope="col">时间</th>      <th width="144" bgcolor="#E2F4F6" scope="col">昵称</th>      <th width="77" bgcolor="#E2F4F6" scope="col">评论数</th>      <th width="71" bgcolor="#E2F4F6" scope="col">删除</th>    </tr><?php do{?>    <tr>      <th height="49" scope="col"><?php echo $commentcount=$result2['id'];?></th>      <th scope="col"><?php echo $result2['zhanghao'];?></th>      <th scope="col"><a href="view.php?id=<?php echo $result2['id'];?>">      <?php echo $result2['title'];?> </a></th>      <th scope="col"><?php echo date("Y-m-d H:i:s",strtotime($result2['time']));?></th>      <th scope="col"><?php echo $result2['name'];?></th>      <th scope="col"> <?php $sql2="select count(*) as abc from tbcomment where id='$commentcount'";    $sqlquery=mysql_query($sql2,$mylink);    $result4=mysql_fetch_array($sqlquery);    echo $result4['abc'];     ?></th>      <th scope="col"><a href="shanchu.php?id=<?php echo $result2['id'];?>"><?php echo "删除";?></a></th>    </tr><?php }while($result2=mysql_fetch_array($result))?>  </table></div><?php }?> 



[解决办法]
$sql="select * from news where title like '$biaoti2'";
$result=mysql_query($sql,$mylink);
$result2=mysql_fetch_array($result);
$i=0;
do
{
$i++;
}
while($result2=mysql_fetch_array($result));这是干什么?
echo "搜索内容:".$biaoti;
echo "</br>";
echo "搜索结果总数:".$i;
if($biaoti=="")
{
echo "模块初始化已完成";

}
else
{
?>
与php无干,略去
<?php do
{
?>
与php无干,略去
<th scope="col"><?php echo date("Y-m-d H:i:s",strtotime($result2['time']));?>$result2已在前面的 do while 中置空了,下同
</th>
<th scope="col"><?php echo $result2['name'];?></th>
<th scope="col"> <?php $sql2="select count(*) as abc from tbcomment where id='$commentcount'";
$sqlquery=mysql_query($sql2,$mylink);
$result4=mysql_fetch_array($sqlquery);
echo $result4['abc'];
?></th>
<th scope="col"><a

href="shanchu.php?id=<?php echo $result2['id'];?>"><?php
echo "删除";?></a></th>
</tr><?php
}
while($result2=mysql_fetch_array($result)) $result是空的如何循环?

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