怎么从一个时间字符串中快速获取年，小时这样的信息
字符串类型是 char*time=“2002-1-2 13:22:50”；然后以%04d%02d%02d%02d%02d%02d的形式输入到一个字符串中

[解决办法]

C/C++ code

#include <stdio.h>int main(int argc, char* argv[]){    char* time = "2002-1-2 13:22:50";    char str[32];    int year;    int month;    int day;    int hour;    int minute;    int second;    sscanf(time, "%d-%d-%d %d:%d:%d", &year, &month, &day, &hour, &minute, &second);    sprintf(str, "%04d%02d%02d%02d%02d%02d", year, month, day, hour, minute, second);    printf("%s\n", str);    return 0;}