【两表进行对比，取最接近的日期的成本价格】
A表为成本表
型号，日期，成本
ccode，cdate，cmoney
801,2012-08-01,120
801,2012-08-05,110
801,2012-08-10,100
802,2012-07-01,80
802,2012-08-10,60
803,2012-08-06,86
B表为导入实际销售情况表
型号，销售日期，实际价格
ccode，selldate，sellmoney
801,2012-08-01,130
801,2012-08-02,130
801,2012-08-08,150
801,2012-08-11,120
802,2012-08-12,100
803,2012-08-13,100
根据销售日期，取成本A表中最接近销售日期的成本价格，计算毛利
最后的结果就是
型号，销售日期，实际价格，成本价格，毛利
801,2012-08-01,130,120,10
801,2012-08-02,130,120,10
801,2012-08-08,150,110,40
801,2012-08-11,120,100,20
802,2012-08-12,100,60,40
803,2012-08-13,100,86,14
[解决办法]
- SQL code
declare @A table(ccode int,cdate datetime,cmoney int)insert into @Aselect 801,'2012-08-01',120 union allselect 801,'2012-08-05',110 union allselect 801,'2012-08-10',100 union allselect 802,'2012-07-01',80 union allselect 802,'2012-08-10',60 union allselect 803,'2012-08-06',86declare @B table(ccode int,selldate datetime,sellmoney int)insert into @Bselect 801,'2012-08-01',130 union allselect 801,'2012-08-02',130 union allselect 801,'2012-08-08',150 union allselect 801,'2012-08-11',120 union allselect 802,'2012-08-12',100 union allselect 803,'2012-08-13',100select t.*,sellmoney-cmoney as 毛利from ( select b.*,(select top 1 cmoney from @A a where a.ccode=b.ccode and datediff(day,a.cdate,b.selldate)>=0 order by a.cdate desc) cmoney from @B b) t/*ccode selldate sellmoney cmoney 毛利----------- ----------------------- ----------- ----------- -----------801 2012-08-01 00:00:00.000 130 120 10801 2012-08-02 00:00:00.000 130 120 10801 2012-08-08 00:00:00.000 150 110 40801 2012-08-11 00:00:00.000 120 100 20802 2012-08-12 00:00:00.000 100 60 40803 2012-08-13 00:00:00.000 100 86 14*/
[解决办法]
用一下上在老兄数据。
;WITH cte AS (
SELECT b.ccode,a.cmoney,b.sellmoney,rr=ROW_NUMBER() OVER(PARTITION BY b.rn ORDER BY ABS(datediff(dd,a.cdate,b.selldate))) FROM @a a join
(SELECT rn=ROW_NUMBER() OVER(ORDER BY GETDATE()),* FROM @b) b
ON a.ccode=b.ccode
)
SELECT *,sellmoney-cmoney FROM cte WHERE rr=1;
/*
ccode cmoney sellmoney rr
----------- ----------- ----------- -------------------- -----------
801 120 130 1 10
801 120 130 1 10
801 100 150 1 50
801 100 120 1 20
802 60 100 1 40
803 86 100 1 14
*/
[解决办法]
- SQL code
SELECT t.*, sellmoney - cmoney AS 毛利FROM ( SELECT b.* , ( SELECT TOP 1 cmoney FROM ta a WHERE a.ccode = b.ccode AND DATEDIFF(day, a.cdate, b.selldate) >= 0 ORDER BY a.cdate DESC ) cmoney FROM tb b ) t
[解决办法]