Struts2中UrlRewriterFilter(url重写)的初步使用

之前做的网站基本成型，不过，听说要对搜索引擎友好点，还得要将网站弄成静态化，至少要做点“伪静态”的工作。而我对url rewrite早有所闻，于是乎就上其官网下了个来玩。入门很简单，下载地址是http://tuckey.org/urlrewrite/dist/urlrewritefilter-2.6.zip，下载来解压。将解压出来的urlrewrite-2.6.0.jar复制到项目中的WEB-INF\lib下，还有urlrewrite.xml复制到WEB-INF下。

接下来就是配置了，配置也是超级简单的。

web.xml里的配置如下，在urlrewrite.xml里面也有注释说明怎么添加的。

??? <! UrlRewriteFilter >
??? <filter>
??????? <filter-name>UrlRewriteFilter</filter-name>
??????? <filter-class>
??????????? org.tuckey.web.filters.urlrewrite.UrlRewriteFilter
??????? </filter-class>
??? </filter>
??? <filter-mapping>
??????? <filter-name>UrlRewriteFilter</filter-name>
??????? <url-pattern>/*</url-pattern>
??? </filter-mapping>

注意将这一段配置放在struts2的配置上面。还要在struts2的配置里加上两行，具体如下：

<! 配置struts2 >
??? <filter>
??????? <filter-name>struts2</filter-name>
??????? <filter-class>
??????????? org.apache.struts2.dispatcher.FilterDispatcher
??????? </filter-class>
??? </filter>

??? <filter-mapping>
??????? <filter-name>struts2</filter-name>
??????? <url-pattern>/*</url-pattern>
??????? <dispatcher>REQUEST</dispatcher>
??????? <dispatcher>FORWARD</dispatcher>
??? </filter-mapping>

?

接下来是修改配置urlrewrite.xml里的内容，它的规则如下：

<urlrewrite>

??? <rule>
??????? <note>
??????????? The rule means that requests to /test/status/ will be redirected to /rewrite-status
??????????? the url will be rewritten.
??????? </note>
??????? <from>/test/status/</from>
??????? <to type="redirect">%{context-path}/rewrite-status</to>
??? </rule>

?

<outbound-rule>
???? <note>
???????? The outbound-rule specifies that when response.encodeURL is called (if you are using JSTL c:url)
???????? the url /rewrite-status will be rewritten to /test/status/.

???????? The above rule and this outbound-rule means that end users should never see the
???????? url /rewrite-status only /test/status/ both in thier location bar and in hyperlinks
???????? in your pages.
???? </note>
???? <from>/rewrite-status</from>
???? <to>/test/status/</to>
</outbound-rule>

?

</urlrewrite>

只要你自己把需要重写的URL规则写上去就好了，我的一个例子就是：

<rule>
??????? <note>shop</note>
??????? <from>/shops.html</from>
??????? <to>/shops/findShops.action</to>
??? </rule>

这样访问shops.html就是访问/shops/findShops.action。

1 楼 weilingfeng98 2011-01-15 可以试试，谢谢了 2 楼 akunamotata 2011-02-04 需要更深入点...