vb6中怎么对二维数组赋值？
我有个矩阵 20 X 18的，全是数字。
我想把他们赋值给一个20*18的数组。
不知道怎么简单点。不会赋值360次吧。要命。给点快的好办法。
刚学！！

[解决办法]
假设两个数组为 A(20,18) B(20,18) ，那么可以这样写

VB code

Dim X As IntegerDim Y As IntegerFor X = 1 To 20    For Y = 1 To 18        B(X, Y) = A(X, Y)    Next YNext X
[解决办法]
那么这样写吧，有一个原始的数组S，赋值为
S = "1,2,3,4,5,6,7,8,9,10;11,12,13,14,15,16,17,18,19,20"
VB code
Dim S As String 'S用来存储所有的数Dim Sp() As StringDim Spl() As StringDim A(20, 18) As Long 'A为最终的数组Dim L1 As Long, L2 As LongS = "1,2,3,4,5,6,7,8,9,10;11,12,13,14,15,16,17,18,19,20"'2x10个，这里就少列出几个了，明白原理的可以再添加'分号、逗号用来分割这二维数组Sp() = Split(S, ";", , vbTextCompare)For L1 = 0 To UBound(Sp)    Spl() = Split(Sp(L1), ",", , vbTextCompare)    For L2 = 0 To UBound(Spl)        A(L1, L2) = CLng(Spl(L2))    Next L2Next L1
[解决办法]
编程习惯要改过来，程序中应该避免大量使用魔术数。
既然是个数据矩阵，先处理一下作成资源比较合理。
[解决办法]
探讨


编程习惯要改过来，程序中应该避免大量使用魔术数。
既然是个数据矩阵，先处理一下作成资源比较合理。

[解决办法]
VB code
dim a(0 to 19,0 to 17) as longdim L as longdim f as integerf=freefile()open "20x18.txt" for input as #ffor i=0 to 359 input #f,L a(i\18,i mod 18)=Lnextclose #f