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C语言倒序输出 I am a Student

发布时间: 2012-09-13 09:51:52 作者: rapoo

C语言倒序输出 I am a Student.

#include <stdio.h>void test() {int a = 0, b = 0, c = a + b;}void main() {char *pi = " 天亮了 我 还 是不是 你的 女人.";int i = 0,  j = 0, k = 0 ;int add[255] = {0};char* cp1 ;printf( "%s -> ", pi );while ( *(pi + i )/* != '\0'*/ ) {if ( *( pi + i ) == ' ' ) {add[k++] = i;}i = i + 1;}for ( i = 1; i < 255; i++ ) { if ( add[ i ] == 0  ) k = i; break; }printf( "%s ", ( pi + add[k - 1] + 1  ) );for ( i = ( k - 2 ); i >= 0 ; i-- ) {j = 1;while ( 1 ) {cp1 = ( char* ) ( *( pi + add[i] + j ) );if ( add[i + 1] == add[i] + j ) break;printf( "%c", cp1 );j = j + 1;} printf( " " );}for ( i = 0; i < add[ 0 ]; i++ )  printf( "%c", ( char* ) *( pi + i ) ); printf( "\n" );system( "pause" );/*cp1 =  (char*) ( *( pi + add[ k - 2 ] )) ;printf( "%c",  cp1  );cp1 =  (char*) ( *( pi + add[ k - 2 ] + 1)) ;printf( "%c",  cp1  );/////////////////////////////////////////////cp1 =  (char*) ( *( pi + add[ k - 3 ] )) ;printf( "%c",  cp1  );cp1 =  (char*) ( *( pi + add[ k - 3 ] + 1)) ;printf( "%c",  cp1  );/////////////////////////////////////////////cp1 =  (char*) ( *( pi + add[ k - 3 ] + 2)) ;printf( "%c ",  cp1  );printf( "%c\n", ( char* ) *( pi ) );*//*printf( "%s\n", ( pi + add[k - 1]  ) );printf( "%s\n", ( pi + add[k - 2]  ) );printf( "%s\n", ( pi + add[k - 2]  ) );printf( "%s\n", ( pi + add[k - 3]  ) );printf( "%s\n", ( pi ) );*/}


 天亮了 我 还 是不是 你的 女人. -> 女人. 你的 是不是 还 我  天亮了请按任意键继续. . .

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