SQL2005 对字段进行拆分
这样才可以把
某一个字段 字符拆分成 多个字段如
准备拆分的



拆分后的




希望有人回答 谢谢了 真心谢谢

[解决办法]

SQL code

declare @str varchar(100)set @str='0000zt0000 5842001314 0000zt0000@163.com'select name1,       email,       reverse(substring(reverse(email),1,charindex('@',reverse(email)))) em,       replace(replace(@str,name1+' ',''),' '+email,'') passfrom(    select substring(@str,0,charindex(' ',@str)) name1,    reverse(substring(reverse(@str),0,charindex(' ',reverse(@str)))) email)t
[解决办法]
探讨

谢谢你的回答 真心感谢
请允许我追问一个问题 
如果是 很多这样的勒

[解决办法]
SQL code
create table #urTable([str] varchar(1000))insert into #urTable select '0000zt0000 5842001314 0000zt0000@163.com'select name1,       email,       reverse(substring(reverse(email),1,charindex('@',reverse(email)))) em,       replace(replace([str],name1+' ',''),' '+email,'') pass from(    select substring([str],0,charindex(' ',[str])) name1,    reverse(substring(reverse([str]),0,charindex(' ',reverse([str])))) email,[str] from #urTable)t/*name1                      email                      em                         pass----------------------------------------------------------------0000zt0000                 0000zt0000@163.com         @163.com                   5842001314(1 行受影响)*/
[解决办法]
create table #urTable([str] varchar(1000))
insert into #urTable select '0000zt0000 5842001314 0000zt0000@163.com'

select name1,
      email,
      reverse(substring(reverse(email),1,charindex('@',reverse(email)))) em,
      replace(replace([str],name1+' ',''),' '+email,'') pass from
(
   select substring([str],0,charindex(' ',[str])) name1,
   reverse(substring(reverse([str]),0,charindex(' ',reverse([str])))) email,[str] from #urTable
)t


[解决办法]
SQL code
create table #urTable([str] varchar(1000))insert into #urTable select '0000zt0000 5842001314 0000zt0000@163.com'select name1,       email,       reverse(substring(reverse(email),1,charindex('@',reverse(email)))) em,       replace(replace([str],name1+' ',''),' '+email,'') pass from(    select substring([str],0,charindex(' ',[str])) name1,    reverse(substring(reverse([str]),0,charindex(' ',reverse([str])))) email,[str] from #urTable)t
[解决办法]
探讨


引用:
SQL code

create table #urTable([str] varchar(1000))
insert into #urTable select '0000zt0000 5842001314 0000zt0000@163.com'

select name1,
email,
reverse(substring(reverse(email……