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datalist里德linkbutton传值,该怎么解

发布时间: 2012-09-14 23:00:49 作者: rapoo

datalist里德linkbutton传值

C# code
 protected void DataList1_ItemCommand(object source, DataListCommandEventArgs e)    {        if (e.CommandName == "look1")        {            Int32 id = Int32.Parse(DataList1.DataKeys[e.Item.ItemIndex].ToString());//获得当前商品编号            Response.Write("<script language='javascript'>window.open('goodslook.aspx?goodid=" + id + "');document.location=document.location;</script>");            //在新窗口中弹出商品详细信息页面        }

C# code
if (!IsPostBack)        {            SqlConnection conn = new SqlConnection(System.Configuration.ConfigurationManager.AppSettings["connstr"]);            conn.Open();            Int32 id = Convert.ToInt32(Request.QueryString["goodsid"]);            string sql = "select * from dbo.Goods where GoodsID=" + id;            SqlDataAdapter sda = new SqlDataAdapter(sql, conn);            DataSet ds = new DataSet();            sda.Fill(ds);           this.Label1.Text = ds.Tables[0].Rows[0][3].ToString();



结果id就变0了..报错了

[解决办法]
注意:地址栏的参数是 goodid 而不是goodsid

所以

C# code
Int32 id = Convert.ToInt32(Request.QueryString["goodsid"]); 

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