请问这样的问题的MySql查询语句怎么写？
现在有一个表，名字就叫作comment吧：
+------+
| id |
+------+
| 102 |
| 203 |
| 213 |
| 222 |
| 258 |
| 288 |
| 298 |
| 322 |
+------+

我想给他按照id顺序加上编号：

+---+-----+
| 编号 | id |
+---+-----+
| 1 | 102 |
| 2 | 203 |
| 3 | 213 |
| 4 | 222 |
| 5 | 258 |
| 6 | 288 |
| 7 | 298 |
| 8 | 322 |
+----+----+
这个我能用以下语句实现：

SQL code

set @floor := 0; select @floor := @floor + 1 as '编号', comment.* from comment

然后我想得到编号4和其后面的2行，在这张表里就会得到如下结果：

+---+-----+
| 编号 | id |
+---+-----+
| 4 | 222 |
| 5 | 258 |
| 6 | 288 |
+----+----+

按照这个实例的步骤，我想请问一般情况下的MySql语句怎么写。我才接触Sql，希望大家能帮助我。谢谢

[解决办法]

SQL code

mysql> SELECT * FROM TA4;+------+| ID   |+------+|  102 ||  203 ||  213 ||  222 ||  258 ||  288 ||  298 ||  322 |+------+8 rows in set (0.00 sec)mysql> SET @NUM:= 0;Query OK, 0 rows affected (0.00 sec)mysql> SELECT * FROM (    -> SELECT *,@NUM:= @NUM + 1 AS '编号' FROM TA4) A ORDER BY 编号 LIMIT 3,3;+------+------+| ID   | 编号     |+------+------+|  222 |    4 ||  258 |    5 ||  288 |    6 |+------+------+3 rows in set (0.00 sec)mysql>
[解决办法]
set @floor := 0; select * from (select @floor := @floor + 1 as `编号`, comment.* from comment) t where `编号`>=4 limit 3;