求：帮我改写下这句SQL语句。。。。
select top 2 *,number=
(select COUNT(*) from et_ztea_images as i where i.tea_albumid=a.id),
imagepath=(select top 1 imagepath from et_ztea_images as z where
z.tea_albumid=a.id),picid=(select top 1 id from et_ztea_images as z
where z.tea_albumid=a.id) from et_ztea_Album as a where teaid=326
order by AlbumTime desc

我想要让 number为0 数据不要（聚合函数方面）。结果就是把第一条数据去掉。。。。。。。。求救各位大哥~
iduserIduserNameteaidtealevelteaAlbumAlbumTime number imagepath picid
139NULLNULL3261xx2012-08-14 0 NULL NULL
47NULLNULL3262xx2012-07-27 3 201272778567.jpg 60

[解决办法]
改下，with语句中不能含有order by,
换成下面的

SQL code

select * from(    select top 2 *,number=    (select COUNT(*) from et_ztea_images as i where i.tea_albumid=a.id),    imagepath=(select top 1 imagepath from et_ztea_images as z where     z.tea_albumid=a.id),picid=(select top 1 id from et_ztea_images as z       where z.tea_albumid=a.id) from et_ztea_Album as a where teaid=326     order by AlbumTime desc) t where number<>0
[解决办法]
SQL code
SELECT TOP 2     * ,     number = ( SELECT COUNT(*) FROM  et_ztea_images AS i WHERE i.tea_albumid = a.id) ,     imagepath = ( SELECT TOP 1 imagepath FROM et_ztea_images AS z WHERE z.tea_albumid = a.id) ,     picid = ( SELECT TOP 1 id FROM et_ztea_images AS z WHERE z.tea_albumid = a.id)FROM  et_ztea_Album AS aWHERE teaid = 326      AND (SELECT COUNT(*) FROM et_ztea_images AS i WHERE i.tea_albumid = a.id) <> 0ORDER BY AlbumTime DESC
[解决办法]
SQL code
SELECT TOP 2        * ,        number = ( SELECT   COUNT(*)                   FROM     et_ztea_images AS i                   WHERE    i.tea_albumid = a.id                 ) ,        imagepath = ( SELECT TOP 1                                imagepath                      FROM      et_ztea_images AS z                      WHERE     z.tea_albumid = a.id                    ) ,        picid = ( SELECT TOP 1                            id                  FROM      et_ztea_images AS z                  WHERE     z.tea_albumid = a.id                )FROM    et_ztea_Album AS aWHERE   teaid = 326AND EXISTS(SELECT 1 FROM et_ztea_images b WHERE a.id = b.tea_albumid)  --加了这句ORDER BY AlbumTime DESC