关于repeater绑定xml特定的某行的数据
- XML code
<?xml version="1.0" encoding="utf-8"?><ErrorInfo> <Error> <LOpertionID ID="20120827164554950"> <StudentID ID="84"> <LQuestionID ID="0"> <LDateID ID="0"> <LErrorReportingID ID="1"> <FErrorNumber ID="0" /> </LErrorReportingID> <LErrorReportingID ID="2"> <FErrorNumber ID="0" /> </LErrorReportingID> <LErrorReportingID ID="3"> <FErrorNumber ID="0" /> </LErrorReportingID> <LErrorReportingID ID="4"> <FErrorNumber ID="0" /> </LErrorReportingID> </LDateID> </LQuestionID> <LQuestionID ID="1"> <LDateID ID="30017"> <LErrorReportingID ID="1"> <FErrorNUmber ID="0" /> </LErrorReportingID> <LErrorReportingID ID="2"> <FErrorNUmber ID="0" /> </LErrorReportingID> <LErrorReportingID ID="3"> <FErrorNUmber ID="0" /> </LErrorReportingID> <LErrorReportingID ID="4"> <FErrorNUmber ID="0" /> </LErrorReportingID> </LDateID> </LQuestionID> </StudentID> </LOpertionID> </Error></ErrorInfo>
请问一下，我要怎么绑定lquestionID为1，LdateID为30017，LErrorReportingID为1的FErrorNumber
这个是我现在的代码
- C# code
protected void Repeater1_ItemDataBound(object sender, RepeaterItemEventArgs e) { if (e.Item.ItemType == ListItemType.Item || e.Item.ItemType == ListItemType.AlternatingItem) { Repeater rep1 = e.Item.FindControl("repnumber1") as Repeater;//找到里层的repeater对象 Repeater rep2 = e.Item.FindControl("repnumber2") as Repeater; Repeater rep3 = e.Item.FindControl("repnumber3") as Repeater; Repeater rep4 = e.Item.FindControl("repnumber4") as Repeater; //DataRowView rowv = (DataRowView)e.Item.DataItem;//找到分类Repeater关联的数据项 //int typeid = Convert.ToInt32(rowv["FID"]); //获取填充子类的id XmlDocument xml = new XmlDocument(); string url = Server.MapPath("Xml\\20120827164554950.xml"); xml.Load(url); XmlNode root = xml.SelectSingleNode("ErrorInfo/Error"); XmlNodeList nodelist = xml.SelectSingleNode("ErrorInfo/Error/LOpertionID/StudentID").ChildNodes; foreach (XmlNode xn1 in nodelist) { XmlElement xe1 = (XmlElement)xn1; if (xe1.GetAttribute("ID") == lid.ToString()) { XmlNodeList lis = xe1.ChildNodes; foreach (XmlNode xn2 in lis) { XmlElement xe2 = (XmlElement)xn2; if (xe2.GetAttribute("ID") == "30016") { XmlNodeList list = xe2.ChildNodes; foreach (XmlNode xn in list) { XmlElement xe = (XmlElement)xn; if (xe.GetAttribute("ID") == "1") { DataSet dss = XmlObject.GetXmlData(url, "ErrorInfo/Error/LOpertionID/StudentID/LQuestionID/LDateID/LErrorReportingID/FErrorNumber"); rep1.DataSource = dss; rep1.DataBind(); } if (xe.GetAttribute("ID") == "2") { DataSet dss = XmlObject.GetXmlData(url, "ErrorInfo/Error/LOpertionID/StudentID/LQuestionID/LDateID/LErrorReportingID/FErrorNumber"); rep2.DataSource = dss; rep2.DataBind(); } if (xe.GetAttribute("ID") == "3") { DataSet dss = XmlObject.GetXmlData(url, "ErrorInfo/Error/LOpertionID/StudentID/LQuestionID/LDateID/LErrorReportingID/FErrorNumber"); rep3.DataSource = dss; rep3.DataBind(); } if (xe.GetAttribute("ID") == "4") { DataSet dss = XmlObject.GetXmlData(url, "ErrorInfo/Error/LOpertionID/StudentID/LQuestionID/LDateID/LErrorReportingID/FErrorNumber"); rep4.DataSource = dss; rep4.DataBind(); break; } } } } }
[解决办法]
用xpath，google一下就知道
[解决办法]
首先不明白你的意思。。Repeater1 这个你是怎么绑定的。。你的这个控件里面再套控件。。这么麻烦。。
你一开始是怎么绑定Repeater1 的。然后这个事件只要根据绑定的 去匹配对应的节点。。。xml有方法可以根据你给定的名称获取到对应的节点，而不需要整体的遍历。。你这个效率相当低啊。。