翻转一个句子，保证单词顺序不变

#include <stdlib.h>#include <stdio.h>#include <string.h>char string[100] = {0};typedef struct data{char content[10];int num;struct data *next;}node;void main(){int i, No = 0, k = 0;char temp[10]= {0};node *data, *head, headNode;head = &headNode;printf("请输入要翻转的字符串：\r\n");gets(string);for(i = 0 ; i <= (int)strlen(string); i++){if (string[i] != ' ' && string[i] != 0){temp[k] = string[i];k++;}else{data = (node *)malloc(sizeof(node));strcpy(data->content, temp);memset(temp, 0, sizeof(temp));data->num = No;k = 0;if(No == 0){head->next = data;data->next = NULL;}else{data->next = head->next;head->next = data;}No++;}}head = headNode.next;printf("\r\n");while(head != NULL){printf("%s ", head->content);data = head;head = head->next;free(data);}printf("\r\nright!!");}