jquery ajax后台返回list,前台用jquery遍历list
$.ajax({type: 'post',url: "maintain_findRoomByBuildingId.shtml",cache: false,data: {"buildingId":buildingId},dataType: 'json',success: function(data){jQuery.each(data.roomList, function(i,item){alert(item.id+","+item.name);});},error: function(){return;}});?