函数执行无法返回值，请大虾帮忙看看的。
CREATE OR REPLACE FUNCTION F_PJ_GDL_SCORE(mXZQDM VARCHAR2,
mNF INT, mYF INT, mFZ FLOAT)
RETURN FLOAT IS
VSCORE FLOAT;
BEGIN
SELECT
(CASE WHEN GDL>=0.75 THEN mFZ
WHEN GDL<0.75 AND GDL>=0.70 THEN (mFZ - 1*1.5)
WHEN GDL<0.70 AND GDL>=0.65 THEN (mFZ - 2*1.5)
WHEN GDL<0.65 AND GDL>=0.60 THEN (mFZ - 3*1.5)
WHEN GDL<0.60 AND GDL>=0.55 THEN (mFZ - 4*1.5)
WHEN GDL<0.55 AND GDL>=0.55 THEN (mFZ - 5*1.5)
WHEN GDL<0.50 AND GDL>=0.55 THEN (mFZ - 6*1.5)
WHEN GDL<0.45 AND GDL>=0.55 THEN (mFZ - 7*1.5)
WHEN GDL<0.40 AND GDL>=0.55 THEN (mFZ - 8*1.5)
WHEN GDL<0.35 AND GDL>=0.30 THEN (mFZ - 9*1.5)
ELSE 0
END ) as FS INTO vSCORE FROM T_PJ_GDL
WHERE XZQ_DM=mXZQDM AND NF=mNF AND YF=mYF;
RETURN vSCORE;
END;

注意SELECT 查询没问题，部知道什么原因无法返回数据的。


[解决办法]

SQL code

--经测，没问题SQL> create table T_PJ_GDL(XZQ_DM varchar2(20),NF int,YF int,GDL float);表已创建。SQL> insert into T_PJ_GDL values('4401',2012,9,0.7);已创建 1 行。SQL> CREATE OR REPLACE FUNCTION F_PJ_GDL_SCORE(mXZQDM VARCHAR2,  2  mNF INT, mYF INT, mFZ FLOAT)  3  RETURN FLOAT IS  4    VSCORE FLOAT;  5  BEGIN  6    SELECT  7    (CASE WHEN GDL>=0.75 THEN mFZ  8    WHEN GDL<0.75 AND GDL>=0.70 THEN (mFZ - 1*1.5)  9    WHEN GDL<0.70 AND GDL>=0.65 THEN (mFZ - 2*1.5) 10    WHEN GDL<0.65 AND GDL>=0.60 THEN (mFZ - 3*1.5) 11    WHEN GDL<0.60 AND GDL>=0.55 THEN (mFZ - 4*1.5) 12    WHEN GDL<0.55 AND GDL>=0.55 THEN (mFZ - 5*1.5) 13    WHEN GDL<0.50 AND GDL>=0.55 THEN (mFZ - 6*1.5) 14    WHEN GDL<0.45 AND GDL>=0.55 THEN (mFZ - 7*1.5) 15    WHEN GDL<0.40 AND GDL>=0.55 THEN (mFZ - 8*1.5) 16    WHEN GDL<0.35 AND GDL>=0.30 THEN (mFZ - 9*1.5) 17    ELSE 0 18    END ) as FS INTO vSCORE FROM T_PJ_GDL 19    WHERE XZQ_DM=mXZQDM AND NF=mNF AND YF=mYF; 20    RETURN vSCORE; 21  END; 22  /函数已创建。SQL> select F_PJ_GDL_SCORE('4401',2012,9,15) from dual;F_PJ_GDL_SCORE('4401',2012,9,15)                                                --------------------------------                                                                            13.5