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JavaWeb快速入门4

发布时间: 2012-10-09 10:21:45 作者: rapoo

JavaWeb快速入门四

servlet 转发

test2

package second;

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import java.io.IOException;

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import javax.servlet.ServletException;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

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public class SecondServlet extends HttpServlet {

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??? public void doGet(HttpServletRequest request, HttpServletResponseresponse)

?????????? throws ServletException, IOException {

?????? request.getRequestDispatcher("/success.jsp").forward(request,response);

??? }

???

??? public void doPost(HttpServletRequest request, HttpServletResponseresponse)

?????????? throws ServletException, IOException {

?????? //post和get是浏览器的两种请求访问方式,这里只要post提交过来的全部交给doGet方法

?????? //get和post在下一例子详说

?????? doGet(request,response);

??? }

? <servlet>

??? <servlet-name>SecondServlet</servlet-name>

??? <servlet-class>second.SecondServlet</servlet-class>

? <servlet-mapping>

??? <servlet-name>SecondServlet</servlet-name>

??? <url-pattern>/servlet/SecondServlet</url-pattern>

<!DOCTYPE HTML PUBLIC "-//W3C//DTDHTML 4.01 Transitional//EN">

<html>

? <body>

??? servlet response success ! <br>

? </body>

</html>

测试地址:http://localhost:8080/test2/servlet/SecondServlet

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