不知道怎么描述 一个select语句 想了三四个小时了

SQL code

CREATE TABLE #TEST (ID INT, SEGMENT CHAR (1),RESPONSES INT,CHECKED SMALLDATETIME)

有表如上

RESPONSES 代表SEGMENT 出现在 日期 CHECKED 的次数，要求：

写一个query 语句 总结 在每个SEGMENT 和 每个CHECKED 的 RESPONSES

不要硬编码 如果以后加了D 或者 Segments 重命名了 应该有相应改变

样本：

SQL code

INSERT INTO #TEST VALUES (1, 'A', 0, '2009-05-01')INSERT INTO #TEST VALUES (2, 'B', 1, '2009-05-01')INSERT INTO #TEST VALUES (3, 'C', 0, '2009-05-01')INSERT INTO #TEST VALUES (4, 'A', 0, '2009-05-02')INSERT INTO #TEST VALUES (5, 'B', 2, '2009-05-02')INSERT INTO #TEST VALUES (6, 'C', 1, '2009-05-02')INSERT INTO #TEST VALUES (7, 'A', 1, '2009-05-03')INSERT INTO #TEST VALUES (8, 'B', 0, '2009-05-03')INSERT INTO #TEST VALUES (9, 'C', 2, '2009-05-03')

输出
CHECKED A B C
1 2009-05-01 0 1 0
2 2009-05-02 0 2 1
3 2009-05-03 1 0 2


[解决办法]

SQL code

DECLARE @s VARCHAR(MAX)SELECT @s=ISNULL(@s+',','')+QUOTENAME(SEGMENT) FROM #TEST GROUP BY  SEGMENTEXEC('SELECT  * FROM        (         SELECT SEGMENT , RESPONSES , CHECKED FROM #TEST        ) AS t PIVOT ( MAX(RESPONSES) FOR SEGMENT IN ('+@s+') ) AS piv')/*CHECKED    A    B    C2009-05-01 00:00:00    0    1    02009-05-02 00:00:00    0    2    12009-05-03 00:00:00    1    0    2*/