c++ 双维数组的问题
通宵做了半天，还是没有成功，只好来请教一下~~~~~~输入N行10列double数字，然后输入。 输入和输入都要用函数，而且必须要用到动态分配数组。想了半宿。。。。无奈啊~~



#include "stdafx.h"
#include<iostream>
using namespace std;
typedef double* doubleP;
void fillArray(double a[][],int row,int column);
void echoing(double a[][]);

int main()
{
int column=10,row;
cout << "enter the number of rows : \n";
cin >> row;
doubleP p;
p=new double[row];
fillArray(p,row,column)
echoing(p,row,10);
}
fillArray(double a[][],int row,10)
{
int i,j;
for(i=0;i<row;i++)
a[i]=new double[10];
cout << "enter "<< column<<"double number per row,";
cout <<"total " <<row <<"rows.\n";
for(i=0;i<row;i++)
for(j=0;j<10;j+=)
cin>>a[i][j];
}

void echoing(double a[][],int row,int column)
{
int i,j;
for(i=0,i<row;i++)
for(j=0;j<column;j++)
cout << a[i][j]<<endl;
}


[解决办法]
int row;
int column=10,row;
cout << "enter the number of rows : \n";
cin >> row;
vector< vector<double> > a(row);
vector<double> b;
int i,j;
double c;
cout << "enter "<< column<<"double number per row,";
cout <<"total " <<row <<"rows.\n";
for(i=0;i<row;i++)
{
for(j=0;j<10;j++)
{
cin>>c;
if (b.size() <= j)
b.push_back(0);
else
b[j] = c;
}
if (a.size() <= i)
a.push_back(b);
else
a[i] = b;
}

[解决办法]

C/C++ code

#include "stdafx.h"#include <iostream>using namespace std;#define COL 3void FillArray(double a[][COL], int row);void PrintArray(double a[][COL], int row);void FillArray(double** a, int row, int col);void PrintArray(double** a, int row, int col);int _tmain(int argc, _TCHAR* argv[]){    int rowNum = 0;    std::cout<<"请输入行数 ："<<std::endl;    std::cin>>rowNum;    if (rowNum <= 0)    {        return 0;    }    //方式1    double (*pArrayA)[COL] = NULL;    pArrayA = new double[rowNum][COL]();    if (pArrayA == NULL)    {        return 0;    }    FillArray(pArrayA, rowNum);    PrintArray(pArrayA,rowNum);    delete [] pArrayA;    //方式2    int colNum = 0;    std::cout<<"请输入列数 ："<<std::endl;    std::cin>>colNum;    double* *pArrayB = NULL;    pArrayB = new  double*[rowNum];    if (pArrayB == NULL)    {        return 0;    }    FillArray(pArrayB, rowNum, colNum);    PrintArray(pArrayB,rowNum,colNum);    for (int i = 0; i < rowNum; i++)    {        delete [] pArrayB[i];    }    delete [] pArrayB;    return 0;}void FillArray(double a[][COL], int row){    double* pArray  = NULL;    for (int i = 0; i < row; i++)    {        pArray = *(a+i);        std::cout<<"请输入第 "<<i+1<<" 行的数据 : "<<std::endl;        for (int j= 0; j < COL; j++)        {            std::cin>>*(pArray+j);        }    }}void PrintArray(double a[][COL], int row){    std::cout<<"已保存的数据为："<<std::endl;    double* pArray  = NULL;    for (int i = 0; i < row; i++)    {        pArray = *(a+i);        for (int j= 0; j < COL; j++)        {            std::cout<<*(pArray+j)<<" ";        }        std::cout<<std::endl;    }    std::cout<<std::endl;}void FillArray(double** a, int row, int col){    for (int i = 0; i < row; i++)    {        *(a+i) = new double[col]();    }    for (int j = 0; j < row; j++)    {        std::cout<<"请输入第 "<<j+1<<" 行的数据 : "<<std::endl;        for (int k = 0; k < col; k++)        {            std::cin>>*(*(a+j)+k);        }    }}void PrintArray(double** a, int row, int col){    std::cout<<"已保存的数据为："<<std::endl;    for (int j = 0; j < row; j++)    {        for (int k = 0; k < col; k++)        {            std::cout<<*(*(a+j)+k)<<" ";        }        std::cout<<std::endl;    }} 
 
[解决办法]
太长没仔细看 动态数组我倒是懂
[解决办法]
刚学的动态数组
cin>>len;
int*p=new
int[len];
..........
delete[]p;
return0