求助一个关于php构建测试表单的问题
- PHP code
<?php$con=mysql_connect("localhost","root","");mysql_select_db("test");mysql_query("set names gb2312");?>这是初始的服务器config.
- PHP code
<?phperror_reporting(E_ALL & ~ E_NOTICE);echo "<center>";if (!$_POST["test_name"]){ echo "<h2>create test</h2>"; echo "<table border=1>"; echo "<form method=post action=".$_SERVER["PHP_SELF"].">"; echo "<tr>"; echo "<td>test question</td>"; echo "<td><input type=text name=test_name></td>"; echo "</tr>"; echo "<tr>"; echo "<td colspan=2><center><input type=submit value=next></center></td>"; echo "</tr>"; echo "</form>"; echo "</table>";}else { include 'config.php'; $content=$_POST["test_name"]; $sql="insert into question('content') values('$content')"; if (mysql_query($sql)) { echo "create test_content successfull!!!"; echo "<p>"; echo "click<a href=add_question.php>here</a>to add question"; } else "error!!!".mysql_error(); mysql_close();}echo "<center>";?>现在问题是这样的,创建不了表单,求大神帮我指点指点...为什么会出现这样的状况..谢谢了
[解决办法]
$sql="insert into question(`content`) values('$content')"; //content的注释符号写错了