帮忙写个正则表达式 ，很简单

NO,Name,Sex,Birthday,Chinese,Math,English,Physics,Chemistry
以NO开头，并且一定要有NO

Name,Sex,Birthday,Chinese,Math,English,Physics,Chemistry 中选择，可以是全部，也可以是没有一个，有某个属性的话一定要有“，”



[解决办法]

C/C++ code

"NO(,((Name)|(Sex)|(Birthday)|(Chinese)|(Math)|(English)|(Physics)|(Chemistry)))*"
[解决办法]
C/C++ code
// RegExpr.cpp : Defines the entry point for the console application.//#include "stdafx.h"#include <iostream>#include <string>#include "regexpr2.h"using namespace std;using namespace regex;int _tmain(int argc, _TCHAR* argv[]){    match_results results;    string strs[] = {        "NO,Name,Sex,Birthday,Chinese,Math,English,Physics,Chemistry ",        "adsfasdf NO, Sex,Birthday,Chinese,Math,English",        "Hello,World",        "  ",        "123 NOhysics,Chemistry ",        "NO,Chinese,Math,English,Physics,Chemistry",        "NO,chinese,MATH,EnglISH,physics,CHEMISTRY",    };    rpattern pat("NO(,(Name|Sex|Birthday|Chinese|Math|English|Physics|Chemistry))*", NOCASE);     for (int i = 0; i < sizeof(strs)/sizeof(strs[0]); ++i)    {        match_results::backref_type br = pat.match( strs[i], results );        if( br.matched )         {                        cout <<i<<" match success : " <<br<< endl;                                }        else        {            cout <<i<<" match failed!"<< endl;                    }    }        return 0;}