JS中得到.nsf库 数据库路径
var pathname = (window.location.pathname);
??var dbpath = pathname.substring(0,(pathname.lastIndexOf('.nsf')+5));
发布时间: 2012-11-04 10:42:41 作者: rapoo
JS中得到.nsf库 数据库路径
var pathname = (window.location.pathname);
??var dbpath = pathname.substring(0,(pathname.lastIndexOf('.nsf')+5));