hibernate HQL语句的参数设置

以hql举列:更多的查帮助

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// 使用List为参数作为条件结果
??????? List<Integer> lst = new ArrayList<Integer>();
??????? lst.add(14);
??????? lst.add(15);
??????? lst.add(17);
??????? String hql = "from Students s where s.SId in (:lst)";
??????? Query q = session.createQuery(hql);
??????? q.setParameterList("lst",lst);

??????? // 以一个实类作为参数条件
??????? hql = "from Students s where s.class=:class";
??????? q.setEntity("class",session.get(Class.class,1));?????

??????? // 根据给的参数匹配对应的类型Type hiberntae里的类
??????? hql = "from Students s where s.SId=? or s.SName=?";
??????? Query q = session.createQuery(hql);
??????? q.setParameters(new Object [] { 14,"update" },new Type [] { new IntegerType(),new StringType() });