select时添加自增的编号（就像oracle中的rowid，rownum） 急！急！急！
- SQL code
mysql> SELECT mobile_num,COUNT(DISTINCT vlr) AS vlrcount FROM alarmdetailGROUP BY mobile_num ORDER BY vlrcount DESC LIMIT 10;+---------------+----------+| mobile_num | vlrcount |+---------------+----------+| 8615868157030 | 4 || 8615888432117 | 4 || 8615888757011 | 3 || 8615824157681 | 3 || 8615888779740 | 3 || 8613806853520 | 3 || 8615824459241 | 3 || 8613566124713 | 3 || 8615888202117 | 3 || 8613566169670 | 3 |+---------------+----------+10 rows in set (0.00 sec)
我想让查询的结果前面有1，2，3，4，...，10这样的编号。这个该怎么搞啊
请大家帮帮忙啊。
在csdn上找到这样的方法，在我的这个结果中不行啊。
- SQL code
mysql> SELECT (SELECT COUNT(1)+1 FROM alarmdetail b WHERE b.idalarmdetail.id ) AS Rank, mobile_num,COUNT(DISTINCT vlr) AS vlrcount -> FROM alarmdetail -> GROUP BY mobile_num -> ORDER BY vlrcount DESC LIMIT 10;+------+---------------+----------+| Rank | mobile_num | vlrcount |+------+---------------+----------+| 132 | 8615868157030 | 4 || 278 | 8615888432117 | 4 || 264 | 8613566233443 | 3 || 1147 | 8613567771731 | 3 || 259 | 8613806853520 | 3 || 1076 | 8615824145234 | 3 || 142 | 8615858155622 | 3 || 1384 | 8615868418510 | 3 || 361 | 8615869009887 | 3 || 337 | 8615869174411 | 3 |+------+---------------+----------+10 rows in set (0.48 sec)
[解决办法]
SELECT mobile_num,COUNT(DISTINCT vlr) AS vlrcount FROM alarmdetail
GROUP BY mobile_num ORDER BY vlrcount DESC LIMIT 10;
存为VIEW NEWTT：
SELECT A.mobile,A.vlrcount,COUNT(B.vlrcount) FROM NEWTT A INNER JOIN NEWTT B
ON A.mobile>=B.mobile GROUP BY A.mobile,A.vlrcount
[解决办法]
2楼３楼都是不错的方法。
[解决办法]
参考下贴中的多种方法。
http://blog.csdn.net/ACMAIN_CHM/archive/2009/04/20/4095531.aspx
MySQL中的ROWNUM的实现
[解决办法]