内存值输出
如何将内存的值输出呢？如整形777输出的字符串为：09 03

[解决办法]
%x 16进制输出
[解决办法]

C/C++ code

#include <iostream>#include <stdio.h>#include <stdlib.h>#include <string.h>#include <ctype.h>void printBinStr(const void* buf , size_t size);void printHexStr(const void* buf , size_t size);void test();int main(int argc, char* argv[]){//   test();    int seven  = 777;    printBinStr(&seven , sizeof(seven));    printHexStr(&seven , sizeof(seven));    return 0;}void test(){    char arr[100];    for (int i = 0; i != 100  ; ++i) {        arr[i] = i + '1';    }    printBinStr(arr , sizeof(arr));    putchar('\n');// 打印文件    const char* filename =  "main.cpp";    FILE* f = fopen(filename, "rb");    if (!f) {        std::cerr << "Error: Cannot open File " << std::endl;        exit(-1) ;    }    // Get file size:    fseek(f, 0, SEEK_END);    const long N = ftell(f);    fclose(f);    f = fopen(filename, "rb");    char* buf = new char[N + 1];    fread(buf, 1, N, f);    buf[N] = '\0';    printHexStr(buf , N);}void printBinStr(const void* buf , size_t size){    unsigned char* str = (unsigned char*)buf;    char line[512] = {0};    const size_t lineLength = 6; // 每行6个字符    char text[24] = {0};    char sbin[10] = {0};    char* pc;    int textLength = lineLength;    for (size_t ix = 0 ; ix < size ; ix += lineLength) {        sprintf(line, "%.8xh: ", ix);// 打印二进制        for (size_t jx = 0 ; jx != lineLength ; jx++) {            itoa(* (str + ix + jx),   sbin,   2);       //转换成字符串，进制基数为2            if (ix + jx >= size) {                sprintf(line + (11 + jx * 9), "         "); // 处理最后一行空白                if (ix + jx == size)                    textLength = jx;  // 处理最后一行文本截断            } else                sprintf(line + (11 + jx * 9), "%08s ", sbin);        }// 打印字符串        {            memcpy(text, str + ix, lineLength);            pc = text;            while (pc != text + lineLength) {                if ((unsigned char)*pc < 0x20) // 空格之前为控制码                    *pc = '.';                 // 控制码转成'.'显示                pc++;            }            text[textLength] = '\0';            sprintf(line + (11 + lineLength * 9), "; %s", text);        }        printf("%s\n", line);    }}void printHexStr(const void* buf , size_t size){    unsigned char* str = (unsigned char*)buf;    char line[512] = {0};    const size_t lineLength = 16; // 8或者32    char text[24] = {0};    char* pc;    int textLength = lineLength;    for (size_t ix = 0 ; ix < size ; ix += lineLength) {        sprintf(line, "%.8xh: ", ix);// 打印16进制        for (size_t jx = 0 ; jx != lineLength ; jx++) {            if (ix + jx >= size) {                sprintf(line + (11 + jx * 3), "   "); // 处理最后一行空白                if (ix + jx == size)                    textLength = jx;  // 处理最后一行文本截断            } else                sprintf(line + (11 + jx * 3), "%.2X ", * (str + ix + jx));        }// 打印字符串        {            memcpy(text, str + ix, lineLength);            pc = text;            while (pc != text + lineLength) {                if ((unsigned char)*pc < 0x20) // 空格之前为控制码                    *pc = '.';                 // 控制码转成'.'显示                pc++;            }            text[textLength] = '\0';            sprintf(line + (11 + lineLength * 3), "; %s", text);        }        printf("%s\n", line);    }}
[解决办法]
C/C++ code
void HexDump(char *buf,int len) {    int i,j,k;    char binstr[80];    for (i=0;i<len;i++) {        if (0==(i%16)) {            sprintf(binstr,"%04x -",i);            sprintf(binstr,"%s %02x",binstr,(unsigned char)buf[i]);        } else if (15==(i%16)) {            sprintf(binstr,"%s %02x",binstr,(unsigned char)buf[i]);            sprintf(binstr,"%s  ",binstr);            for (j=i-15;j<=i;j++) {                sprintf(binstr,"%s%c",binstr,('!'<buf[j]&&buf[j]<='~')?buf[j]:'.');            }            printf("%s\n",binstr);        } else {            sprintf(binstr,"%s %02x",binstr,(unsigned char)buf[i]);        }    }    if (0!=(i%16)) {        k=16-(i%16);        for (j=0;j<k;j++) {            sprintf(binstr,"%s   ",binstr);        }        sprintf(binstr,"%s  ",binstr);        k=16-k;        for (j=i-k;j<i;j++) {            sprintf(binstr,"%s%c",binstr,('!'<buf[j]&&buf[j]<='~')?buf[j]:'.');        }        printf("%s\n",binstr);    }}