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急求！该如何解决

发布时间： 2012-12-15 15:16:03 作者： rapoo

急求！！！！
sqlserver数据库中怎样获取2012-10-10到2012-11-30的所有周，（并且显示是一年中的第几周）？急用！！！谢谢大家。
[最优解释]
添加:期

USE test
GO


---->生成表tb
--if object_id('tb') is not null 
--drop table tb
--Go
---- test data
--Create table tb([日期] datetime,[OrderNr] nvarchar(3),[CustomerName] nvarchar(1))
--Insert into tb
--Select '2012-01-01',N'#1',N'A'
--Union all Select '2012-01-02',N'#2',N'A'
--Union all Select '2012-01-03',N'#3',N'A'
--Union all Select '2012-01-04',N'#4',N'A'
--Union all Select '2012-02-01',N'#5',N'A'
--Union all Select '2012-02-02',N'#6',N'B'
--Union all Select '2012-02-03',N'#7',N'B'
--Union all Select '2012-05-14',N'#8',N'B'
--Union all Select '2012-05-16',N'#9',N'C'
--Union all Select '2012-05-18',N'#10',N'B'
--Union all Select '2012-05-19',N'#11',N'C'
--Union all Select '2012-09-05',N'#12',N'A'
--Union all Select '2012-09-06',N'#13',N'D'
--Union all Select '2012-09-07',N'#14',N'D'
--Union all Select '2013-01-06',N'#14',N'D'
--Union all Select '2013-01-07',N'#14',N'D'


;WITH Result AS (
SELECT YEAR(日期) AS [Year],DATEPART(Week,日期) AS [Week],* FROM tb
)
SELECT 
COUNT(a.日期) AS [Count]
,b.[Week]
,b.[Year]
FROM Result AS a
RIGHT JOIN (                                                                                                                                
SELECT
t.Year,t2.Week 
FROM (
SELECT DISTINCT 
Year 
FROM Result
) t,(
SELECT TOP 52 
ROW_NUMBER()OVER(ORDER BY getdate()) AS [Week] 
FROM sys.syscolumns
) t2
WHERE t2.Week>=(SELECT MIN(Week) FROM Result AS x WHERE x.Year=t.Year)
AND t2.Week<=(SELECT MAX(Week) FROM Result AS x WHERE x.Year=t.Year)
) AS b ON a.Year=b.Year AND a.Week=b.Week
GROUP BY b.[Week],b.[Year]
ORDER BY b.[Year],b.[Week]


/*
Count  Week  Year
------ ----- -----
4      1     2012
0      2     2012
0      3     2012
0      4     2012
3      5     2012
0      6     2012 
 
0      7     2012
0      8     2012
0      9     2012
0      10    2012
0      11    2012
0      12    2012
0      13    2012
0      14    2012
0      15    2012
0      16    2012
0      17    2012
0      18    2012
0      19    2012
4      20    2012
0      21    2012
0      22    2012
0      23    2012
0      24    2012
0      25    2012
0      26    2012
0      27    2012
0      28    2012
0      29    2012
0      30    2012
0      31    2012
0      32    2012
0      33    2012
0      34    2012
0      35    2012
3      36    2012
2      2     2013
*/

[其他解释]

select 
DATEADD(dd,number,'2012-10-10') dt,
datepart(WK,DATEADD(dd,number,'2012-10-10'))  as wk
from
master..spt_values
where
number between 0 and DATEDIFF(dd,'2012-10-10','2012-11-30')
and type='p'
/*
dt                      wk
----------------------- -----------
2012-10-10 00:00:00.000 41
2012-10-11 00:00:00.000 41
2012-10-12 00:00:00.000 41
2012-10-13 00:00:00.000 41
2012-10-14 00:00:00.000 42
2012-10-15 00:00:00.000 42
2012-10-16 00:00:00.000 42
2012-10-17 00:00:00.000 42
2012-10-18 00:00:00.000 42
2012-10-19 00:00:00.000 42
2012-10-20 00:00:00.000 42
2012-10-21 00:00:00.000 43
2012-10-22 00:00:00.000 43
2012-10-23 00:00:00.000 43
2012-10-24 00:00:00.000 43
2012-10-25 00:00:00.000 43
2012-10-26 00:00:00.000 43
2012-10-27 00:00:00.000 43
2012-10-28 00:00:00.000 44
2012-10-29 00:00:00.000 44
2012-10-30 00:00:00.000 44
2012-10-31 00:00:00.000 44
2012-11-01 00:00:00.000 44
2012-11-02 00:00:00.000 44
2012-11-03 00:00:00.000 44
2012-11-04 00:00:00.000 45
2012-11-05 00:00:00.000 45 
 
2012-11-06 00:00:00.000 45
2012-11-07 00:00:00.000 45
2012-11-08 00:00:00.000 45
2012-11-09 00:00:00.000 45
2012-11-10 00:00:00.000 45
2012-11-11 00:00:00.000 46
2012-11-12 00:00:00.000 46
2012-11-13 00:00:00.000 46
2012-11-14 00:00:00.000 46
2012-11-15 00:00:00.000 46
2012-11-16 00:00:00.000 46
2012-11-17 00:00:00.000 46
2012-11-18 00:00:00.000 47
2012-11-19 00:00:00.000 47
2012-11-20 00:00:00.000 47
2012-11-21 00:00:00.000 47
2012-11-22 00:00:00.000 47
2012-11-23 00:00:00.000 47
2012-11-24 00:00:00.000 47
2012-11-25 00:00:00.000 48
2012-11-26 00:00:00.000 48
2012-11-27 00:00:00.000 48
2012-11-28 00:00:00.000 48
2012-11-29 00:00:00.000 48
2012-11-30 00:00:00.000 48

(52 行受影响)


*/

[其他解释]
没人吗？自己顶
[其他解释]
引用:
SQL code?1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556575859606162636465666768select DATEADD(dd,number,'2012-10-10') dt, d……


我的表中的数据是从2012-10-10到2012-11-20的，请问应该怎么取，并返回某一周的数据数量？
[其他解释]
你给出测试数据和你想要的结果吧
[其他解释]
引用:
你给出测试数据和你想要的结果吧


count week year
2 42 2012
4 43 2012
7 44 2012
28 45 2012
98 46 2012
148 47 2012
65 48 2012

就是类似于这种的。count就是这周的数据量，week是第几周
[其他解释]
;with t
as(
select 
    DATEADD(dd,number,'2012-10-10') dt,
    datepart(WK,DATEADD(dd,number,'2012-10-10'))  as wk,
number
from
    master..spt_values
where
    number between 0 and DATEDIFF(dd,'2012-10-10','2012-11-30')
    and type='p'
)
select
YEAR(dt) as Years,
wk,
count(1) as CountDays,
sum(number) as counts
from
t
group by
YEAR(dt),
wk
/*
Years(年)       wk(周)         CountDays(这一周多少天)   counts(number的求和)
----------- ----------- ----------- -----------
2012        41          4           6
2012        42          7           49 
 
2012        43          7           98
2012        44          7           147
2012        45          7           196
2012        46          7           245
2012        47          7           294
2012        48          6           291

(8 行受影响)




*/

[其他解释]
引用:
SQL code?12345678910111213141516171819202122232425262728293031323334353637383940;with tas(select DATEADD(dd,number,'2012-10-10') dt, datepart(WK,DATEADD(dd,number,'2012-10-10')) a……


刚刚我试了一下 没有执行成功。我的要求就是把数据表里的数据从第一条数据的创建时间到最后一条数据的创建时间按照周度统计出来每周的数据量。如果有某一周没有数据的话就是0.有数据的话就是数据量。这样说你明白吗？
[其他解释]
引用:
引用:SQL code?12345678910111213141516171819202122232425262728293031323334353637383940;with tas(select DATEADD(dd,number,'2012-10-10') dt, datepart(WK,DATEADD(dd,numb……


自己把你的原表的测试数据贴出来


[其他解释]
似於?
select year(日期) as [Year],datepart(week,日期) as [Week],count(1) as [Count] from tb Group by year(日期),datepart(week,日期)

[其他解释]
顶
[其他解释]
引用:
似於?
SQL code?1select year(日期) as [Year],datepart(week,日期) as [Week],count(1) as [Count] from tb Group by year(日期),datepart(week,日期)


嗯 类似于这样 但是这样只能查出有数据的，比如47周有数据，49周有数据，但是48周没有数据就不显示直接跳过48周了，我想即便没有数据也要显示出来并显示0.你明白我的意思吗
[其他解释]
USE test
GO


---->生成表tb
--if object_id('tb') is not null 
--drop table tb
--Go
---- test data
--Create table tb([日期] datetime,[OrderNr] nvarchar(3),[CustomerName] nvarchar(1))
--Insert into tb
--Select '2012-01-01',N'#1',N'A'
--Union all Select '2012-01-02',N'#2',N'A'
--Union all Select '2012-01-03',N'#3',N'A'
--Union all Select '2012-01-04',N'#4',N'A'
--Union all Select '2012-02-01',N'#5',N'A'
--Union all Select '2012-02-02',N'#6',N'B'
--Union all Select '2012-02-03',N'#7',N'B' 
 
--Union all Select '2012-05-14',N'#8',N'B'
--Union all Select '2012-05-16',N'#9',N'C'
--Union all Select '2012-05-18',N'#10',N'B'
--Union all Select '2012-05-19',N'#11',N'C'
--Union all Select '2012-09-05',N'#12',N'A'
--Union all Select '2012-09-06',N'#13',N'D'
--Union all Select '2012-09-07',N'#14',N'D'


SELECT 
COUNT(a.日期) AS [Count]
,b.[Week]
,b.[Year]
FROM tb AS a
RIGHT JOIN (                                                                                                                                
SELECT * FROM (
SELECT 
YEAR(日期) AS [Year] 
FROM tb 
GROUP BY YEAR(日期)
) t,(
SELECT TOP 52 
ROW_NUMBER()OVER(ORDER BY getdate()) AS [Week] 
FROM sys.syscolumns
) t2

) AS b ON YEAR(a.日期)=b.Year AND DATEPART(week,a.日期)=b.Week
GROUP BY b.[Week],b.[Year]


/*
Count  Week   Year
------ ------ -----
4      1      2012
0      2      2012
0      3      2012
0      4      2012
3      5      2012
0      6      2012
0      7      2012
0      8      2012
0      9      2012
0      10     2012
0      11     2012
0      12     2012
0      13     2012
0      14     2012
0      15     2012
0      16     2012
0      17     2012
0      18     2012
0      19     2012
4      20     2012
0      21     2012
0      22     2012
0      23     2012
0      24     2012
0      25     2012 
 
0      26     2012
0      27     2012
0      28     2012
0      29     2012
0      30     2012
0      31     2012
0      32     2012
0      33     2012
0      34     2012
0      35     2012
3      36     2012
0      37     2012
0      38     2012
0      39     2012
0      40     2012
0      41     2012
0      42     2012
0      43     2012
0      44     2012
0      45     2012
0      46     2012
0      47     2012
0      48     2012
0      49     2012
0      50     2012
0      51     2012
0      52     2012
*/

[其他解释]
顶！

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