一个转换的问题,急!!!!!!!!!!!!!!
CREATE TABLE T(
id INT IDENTITY(1,1),
name VARCHAR(50)
)
INSERT INTO T(name)
SELECT '张三' union
SELECT '李四' union
SELECT '王五'
SELECT * FROM t
/*
得到的结果
id name
1李四
2王五
3张三
*/
/*
想要的结果
id name
1,2,3 李四,王五,张三
*/
求高人帮解,不胜感激
[最优解释]
--CREATE TABLE R
--(
-- id INT ,
-- RelationId INT,--对应T表中的id
--)
--INSERT INTO R(id,RelationId)
--SELECT 1,2 UNION
--SELECT 1,3 UNION
--SELECT 2,1 UNION
--SELECT 2,3 UNION
--SELECT 3,1 UNION
--SELECT 3,2
--CREATE TABLE T(
--id INT IDENTITY(1,1),
--name VARCHAR(50)
--)
--INSERT INTO T(name)
--SELECT '张三' union
--SELECT '李四' union
--SELECT '王五'
--SELECT * FROM t
;WITH test AS
(
SELECT r.id,RelationId,t.name
FROM t INNER JOIN r ON t.id=r.RelationId
)
--SELECT * FROM test
select a.id,
stuff((select ','+CONVERT(VARCHAR(10),RelationId) from test b
where b.id=a.id
for xml path('')),1,1,'') 'RelationId',
stuff((select ','+CONVERT(VARCHAR(10),name) from test b
where b.id=a.id
for xml path('')),1,1,'') 'name'
from test a
group by a.id
/*
id RelationId name
----------- ---------------------------------------------------------------------------------------------------------------- ----------------------------------------------------------------------------------------------------------------
1 2,3 王五,张三
2 1,3 李四,张三
3 1,2 李四,王五
*/
/*
id name
---------------------------------------------------------------------------------------------------------------- ----------------------------------------------------------------------------------------------------------------
1,2,3
*/
[其他解释]
CREATE TABLE T(
id INT IDENTITY(1,1),
name VARCHAR(50)
)
INSERT INTO T(name)
SELECT '张三' union
SELECT '李四' union
SELECT '王五'
declare @id varchar(100)
declare @name varchar(100)
SELECT @id=isnull(@id+',','')+convert(varchar(10),id),@name=isnull(@name+',','')+[name] FROM t
select @id as id,@name as [name]
[其他解释]
SELECT STUFF((SELECT ','+LTRIM(id) FROM t FOR XML PATH('')),1,1,'') AS id,
STUFF((SELECT ','+name FROM t ORDER BY name FOR XML PATH('')),1,1,'') AS NAME
/*
idname
1,2,3李四,王五,张三
*/[其他解释]
这。。。
[其他解释]
CREATE TABLE T(
id INT IDENTITY(1,1),
name VARCHAR(50)
)
INSERT INTO T(name)
SELECT '张三' union
SELECT '李四' union
SELECT '王五'
SELECT * FROM t
SELECT DISTINCT stuff((select ','+CONVERT(VARCHAR(10),id) from t b
for xml path('')),1,1,'') 'id',
stuff((select ','+name from t c
for xml path('')),1,1,'') 'name'
from t a
/*
id name
---------------------------------------------------------------------------------------------------------------- ----------------------------------------------------------------------------------------------------------------
1,2,3
*/
[其他解释]
结果没截全。
id name
---------------------------------------------------------------------------------------------------------------- ----------------------------------------------------------------------------------------------------------------
1,2,3 李四,王五,张三
[其他解释]
不要用文本格式显示结果 就不会出现这种问题了。
[其他解释]
各位不好意思,漏了一个条件,希望大家帮我继续解决,如感觉分不够,请回帖告知,我可以加分的
CREATE TABLE R
(
id INT ,
RelationId INT,--对应T表中的id
)
INSERT INTO R(id,RelationId)
SELECT 1,2 UNION
SELECT 1,3 UNION
SELECT 2,1 UNION
SELECT 2,3 UNION
SELECT 3,1 UNION
SELECT 3,2
/*
想要的结果
RelationID id Name
12,3 王五,张三
21,3李四,张三
31,2 李四,王五
*/
[其他解释]
分不够分啊~~~~其他人你也不好意思不给吧
[其他解释]
没事,只要帮忙解决,肯定加分,先加20分以表诚意
[其他解释]
还没结贴?还有问题吗?
------其他解决方案--------------------
我正在搞联合查询的问题,然后试试这个方法
[其他解释]
额~~~~那不打扰你了。月底了,搞好了结贴,
[其他解释]
select r.relationid,
stuff(
(
select ','+[name] from r as rr,t where rr.id=t.id and r.relationid=rr.relationid order by rr.id for xml path('')
),1,1,''
) as [name],
stuff(
(
select ','+convert(varchar(10),rr.id) from r as rr,t where rr.id=t.id and r.relationid=rr.relationid order by rr.id for xml path('')
),1,1,''
) as id
from r
order by r.relationid