重新提问：51单片机四位数码管，不用锁存器，怎么写？
图：数码管是共阴，但打开完全不亮。

我试过，display函数如果写成wela=1再给P0赋值再wela=0屏幕能有显示，

但1234会显示成4123！而wela1，即P2^4确实控制1。

这样。到底显示函数应该怎么写呢？谢谢各位！

#include<reg52.h>

unsigned char clear = 0xff;  

sbit wela1 = P2^4;
sbit wela2 = P2^5;
sbit wela3 = P2^6;
sbit wela4 = P2^7;
unsigned char code table[] = {0x3f,0x06,0x5b,0x4f,
                                0x66,0x6d,0x7d,0x07,
                               0x7f,0x6f,0x77,0x7c,
                                 0x39,0x5e,0x79,0x71,0};

void delay(int z)
{
    int x,y;
    for(x=z;x>0;x--)
        for(y=110;y>0;y--);
}
void display( char one,char two,char three,char four )
{
     wela1 = wela2 = wela3 = wela4 = 1;
     
    
     wela1 = 0;
     P0 = clear;
     P0 = table[one];
     wela1 = 1;
     delay(5);
     

     wela2 = 0;
     P0 = clear;
     P0 = table[two];
     wela2 = 1;
     delay(5);
     

     wela3 = 0;
     P0 = clear;
     P0 = table[three];
     wela3 = 1;
     delay(5);
     

     wela4 = 0;
     P0 = clear;
     P0 = table[four];
     wela4 = 1;
     delay(5);
}

void main()
{
    display(1,2,3,4);
}

[最优解释]
void display( char one,char two,char three,char four )
{
wela1 = wela2 = wela3 = wela4 = 1;


wela1 = 0;
P0 = clear;
P0 = table[one];
delay(5);
wela1 = 1;


wela2 = 0;
P0 = clear;
P0 = table[two];
delay(5);
wela2 = 1;

wela3 = 0;
P0 = clear;
P0 = table[three];
delay(5);
wela3 = 1;

wela4 = 0;
P0 = clear;
P0 = table[four];
delay(5);
wela4 = 1;}

[其他解释]
顶起来……谢谢各位高手！！
[其他解释]
谢谢！我明白了，
P0 = clear;
P0 = table[four];
wela4 = 0;
delay(5);
wela4 = 1;
只要位选打开的时间有个延时。
这样也可以。
如果用锁存器，是给了锁存器值，这时候不用延时直接关闭，因为有锁存器也没影响。
[其他解释]
可以把程序发给我吗？357700682@qq.com谢谢