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common-fileupload 范例

发布时间: 2012-12-20 09:53:21 作者: rapoo

common-fileupload 实例

common-fileupload是jakarta项目组开发的一个功能很强大的上传文件组件

下面先介绍上传文件到服务器(多文件上传):

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
import java.util.regex.*;
import org.apache.commons.fileupload.*;

public class upload extends HttpServlet {
? private static final String CONTENT_TYPE = "text/html; charset=GB2312";
? //Process the HTTP Post request
? public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
??? response.setContentType(CONTENT_TYPE);
??? PrintWriter out=response.getWriter();
??? try {
??? DiskFileUpload fu = new DiskFileUpload();
?// 设置允许用户上传文件大小,单位:字节,这里设为2m
?fu.setSizeMax(2*1024*1024);
?// 设置最多只允许在内存中存储的数据,单位:字节
?fu.setSizeThreshold(4096);
?// 设置一旦文件大小超过getSizeThreshold()的值时数据存放在硬盘的目录
?fu.setRepositoryPath("c:\\windows\\temp");
?//开始读取上传信息
?List fileItems = fu.parseRequest(request);
?// 依次处理每个上传的文件
?? Iterator iter = fileItems.iterator();

//正则匹配,过滤路径取文件名
?? String regExp=".+\\\\(.+)$";

//过滤掉的文件类型
String[] errorType={".exe",".com",".cgi",".asp"};
?? Pattern p = Pattern.compile(regExp);
?????while (iter.hasNext()) {
?????? FileItem item = (FileItem)iter.next();
?????? //忽略其他不是文件域的所有表单信息
?????? if (!item.isFormField()) {
?????????? String name = item.getName();
?????????? long size = item.getSize();
?????????? if((name==null||name.equals("")) && size==0)
?????????????? continue;
???????Matcher m = p.matcher(name);
?????? boolean result = m.find();
?????? if (result){
?????????? for (int temp=0;temp<ERRORTYPE.LENGTH;TEMP++){
?????????? if (m.group(1).endsWith(errorType[temp])){
???????????????? throw new IOException(name+": wrong type");
?????????? }
?????????? }
?????????? try{

???????? //保存上传的文件到指定的目录

???????? //在下文中上传文件至数据库时,将对这里改写
???????????item.write(new File("d:\\" + m.group(1)));

?????????? out.print(name+"??"+size+"");
?????????? }
?????????? catch(Exception e){
???????????? out.println(e);
?????????? }

????? ? }
?????? else
?????? {
???????? throw new IOException("fail to upload");
?????? }
?????? }
?? }
}
?catch (IOException e){
?? out.println(e);
?}
?catch (FileUploadException e){
????? out.println(e);
?}
?
? }
}

现在介绍上传文件到服务器,下面只写出相关代码:

以sql2000为例,表结构如下:

字段名:name??? filecode

类型: varchar???? image

数据库插入代码为:PreparedStatement pstmt=conn.prepareStatement("insert into test values(?,?)");

代码如下:

。。。。。。

??????try{
????????这段代码如果不去掉,将一同写入到服务器中
????????//item.write(new File("d:\\" + m.group(1)));
?????????????
????????int byteread=0;
????????//读取输入流,也就是上传的文件内容
????????InputStream inStream=item.getInputStream();??????????????
pstmt.setString(1,m.group(1));
????????pstmt.setBinaryStream(2,inStream,(int)size);
????????pstmt.executeUpdate();
????????inStream.close();

????????out.println(name+"??"+size+" ");
????????}

。。。。。。

这样就实现了上传文件至数据库

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