求解决简单的jsp中文乱码问题。高分求指教
错误是这样的：type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: An exception occurred processing JSP page /t3.jsp at line 32
29: </form>
30: <%
31: String name=request.getParameter("use");
32: out.print("提交的数据为："+new String(name.getBytes("ISO-8859-1"),"GB2312"));
33: %>
34: </body>
35: </html>
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:568)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
root cause
java.lang.NullPointerException
org.apache.jsp.t3_jsp._jspService(t3_jsp.java:99)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
note The full stack trace of the root cause is available in the Apache Tomcat/7.0.23 logs.
代码是这个：我也知道要转编码呀！为什么还是错了了？？？请指教
<%@ page language="java" import="java.util.*" pageEncoding="gb2312"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
</head>
<body>
<form action="/h1/servlet/k1" method="post">
<input type="text " name="use">
<input type="submit" value="求和">
</form>
</body>
</html>
[最优解释]
你一开始打开这个页面的时候都没有use的值，你就去取，然后还引用其方法getBytes，不报错才怪了
[其他解释]
<%@ page language="java" import="java.util.*" pageEncoding="gb2312"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
</head>
<body>
<form action="t3.jsp" method="post">
<input type="text" name="use">
<input type="submit" value="提交">
</form>
<%
String name=request.getParameter("use");
out.print("提交的数据为："+new String(name.getBytes("ISO-8859-1"),"GB2312"));
%>
</body>
</html>
代码是这个。。上面的那个贴错了。这个为什么是报错了
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: An exception occurred processing JSP page /t3.jsp at line 32
29: </form>
30: <%
31: String name=request.getParameter("use");
32: out.print("提交的数据为："+new String(name.getBytes("ISO-8859-1"),"GB2312"));
33: %>
34: </body>
35: </html>