数据库重复替换
有一个userinfo 表，把name字段有重复的值替换成原先name+[1-n]
比如 name中有重复n个"a" 替换成a1，a2 , a3, a4, a5...an
[最优解释]
;with cte as
(select *, Case (ROW_NUMBER() over(partition by name order by GetDate())-1) when 0 then Name else Name+rtrim(ROW_NUMBER() over(partition by Name order by GetDate())-1) end as nID from userinfo)

update cte set name=nID
[其他解释]
select *,name+rtrim(select row_number() over(partition by name order by getdate())) from userinfo
[其他解释]
不好意思，更正一下，当只要不重复的时候，直接显示原先的值的！要得到结果是

比如 name中有重复n个"a" 替换成a, a1，a2 , a3, a4, a5...an


并更新原来的表
[其他解释]
;with cte as
(select *, name + CAST( ROW_NUMBER() over(partition by name order by GetDate()) as varchar(5) ) as nID from userinfo)

update cte set name=nID
[其他解释]
可以用一条语句实现吗？
[其他解释]

引用:

;with cte as
(select *, name + CAST( ROW_NUMBER() over(partition by name order by GetDate()) as varchar(5) ) as nID from userinfo)

update cte set name=nID

当只有一条记录的时候，或是第一条记录的时候，不做更新的！a,a1,a2....
[其他解释]

引用:

;with cte as
(select *, Case (ROW_NUMBER() over(partition by name order by GetDate())-1) when 0 then Name else Name+rtrim(ROW_NUMBER() over(partition by Name order by GetDate())-1) end as nID from ……

可以用同一条语句实现吗？
[其他解释]

引用:

;with cte as
(select *, Case (ROW_NUMBER() over(partition by name order by GetDate())-1) when 0 then Name else Name+rtrim(ROW_NUMBER() over(partition by Name order by GetDate())-1) end as nID from ……

可以了，非常感谢！