JSP里web.xml实现错误处理页面的制作404,和500
web.xml文件增加如下代码查看复制到剪切板打印
<error-page>??
??????? <error-code>404</error-code>??
??????? <location>/building.jsp</location>??
</error-page>??
<error-page>??
??????? <error-code>500</error-code>??
??????? <location>/error.jsp</location>??
</error-page>?
??????? <error-page>
??????????????? <error-code>404</error-code>
??????????????? <location>/building.jsp</location>
??????? </error-page>
??????? <error-page>
??????????????? <error-code>500</error-code>
??????????????? <location>/error.jsp</location>
??????? </error-page>building.jsp查看复制到剪切板打印
<%@ page language="java" contentType="text/html; charset=GBK" isErrorPage="true" pageEncoding="GBK"%>??
<%??
? response.setStatus(HttpServletResponse.SC_OK);??
%>??
对不起，您请求的页面没有找到!?
<%@ page language="java" contentType="text/html; charset=GBK" isErrorPage="true" pageEncoding="GBK"%>
<%
? response.setStatus(HttpServletResponse.SC_OK);
%>
对不起，您请求的页面没有找到!error.jsp查看复制到剪切板打印
<%@ page language="java" contentType="text/html; charset=GBK" isErrorPage="true" pageEncoding="GBK"%>??
<%@ page import="java.io.*,java.util.*"%>??
<%response.setStatus(HttpServletResponse.SC_OK);??
?
????? %>??
<body>??
程序发生了错误，有可能该页面正在调试或者是设计上的缺陷.??
?
你可以选择??
?<a href=<%=request.getContextPath()+"/forum/new.jsp" %>>反馈</a>??
提醒我... 或者??
<a href="javascript:history.go(-1)">返回上一页</a>??
<hr width=80%>??
<h2><font color=#DB1260>JSP Error Page</font></h2>??
?
<p>Anexception was thrown: <b><%=exception.getClass()%>:<%=exception.getMessage()%></b></p>??
<%??
System.out.println("Header....");??
Enumeration<String> e = request.getHeaderNames();??
String key;??
while(e.hasMoreElements()){??
? key = e.nextElement();??
? System.out.println(key+"="+request.getHeader(key));??
}??
System.out.println("Attribute....");??
e = request.getAttributeNames();??
while(e.hasMoreElements()){??
? key = e.nextElement();??
? System.out.println(key+"="+request.getAttribute(key));??
}??
?
System.out.println("arameter....");??
e = request.getParameterNames();??
while(e.hasMoreElements()){??
? key = e.nextElement();??
? System.out.println(key+"="+request.getParameter(key));??
}??
%>??
111<%=request.getAttribute("javax.servlet.forward.request_uri") %>??
?
<%=request.getAttribute("javax.servlet.forward.servlet_path") %>??
?
<p>With the following stack trace:</p>??
<pre>??
<%exception.printStackTrace();??
????? ByteArrayOutputStream ostr = new ByteArrayOutputStream();??
????? exception.printStackTrace(new PrintStream(ostr));??
????? out.print(ostr);??
??? %>??
</pre>??
<hr width=80%>??
</body>