Arrays.sort()的用法 排序一

String[] locals=new String[dnats.size()];
????for(int i=0;i<dnats.size();i++){
?????
?????String local_port=dnats.get(i).element("local_port").getText();
?????locals[i]=local_port;
????}
????
????Arrays.sort(locals);
????
????for(int i=0;i<locals.length;i++){
?????String lo=locals[i];
?????String lo1="";//小
?????String lo2="";//大
?????if(i==0){
??????lo2=locals[i+1];
??????if(lo.equals(lo2)){
???????return false;
??????}
?????}
?????else if(i==locals.length-1){
??????lo1=locals[i-1];
??????if(lo.equals(lo1)){
???????return false;
??????}
?????}else{
??????lo1=locals[i-1];
??????lo2=locals[i+1];
??????if(lo.equals(lo1) || lo.equals(lo2)){
???????return false;
??????}
?????}