递归计算1/1+1/2+1/3+...+1/100

/* * 计算 1/1+1/2+1/3+...+1/100 的值 */#include<stdio.h>#include<stdlib.h> double getsum(int n){   if(n==1)return 1.0/1;   else return 1.0/n+getsum(n-1);}int main(){   int n=100;   double result=getsum(n);   printf("result=%f\n",result);}

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