jquery ajax select

$.ajax({
  type: 'POST',
  url: "${base}/smallLine/findSmallByBigLineId.do",
  data: "bigLineId="+bigLine,
  success: function(data){
  $("#smallLineId").empty();
  $("#smallLineId").html("");
  var options = "";
  for ( var i = 0; i < data.smallLinesList.length; i++) {
  var smallLine = data.smallLinesList[i];
  options+="<option value='"+smallLine.id+"'>"+smallLine.name+"</option>";
  }
  $("#smallLineId").append(options);
  $("#smallLineId").html(options);
  $("#smallLine").attr("style","");
  },
  dataType: "json"
});

[最优解释]
success: function(data){
$("#smallLineId").empty();
// $("#smallLineId").html("");
var options = "";
for ( var i = 0; i < data.smallLinesList.length; i++) {
var smallLine = data.smallLinesList[i];
options="<option value='"+smallLine.id+"'>"+smallLine.name+"</option>";
$("#smallLineId").append(options);
}

// $("#smallLineId").html(options);
$("#smallLine").attr("style","");
},
[其他解释]

var options = "";
for ( var i = 0; i < data.smallLinesList.length; i++) {
 var smallLine = data.smallLinesList[i];
  options+="<option value='"+smallLine.id+"'>"+smallLine.name+"</option>"; 
 
       }
   $("#smallLineId").append($(options));

这样呢？
[其他解释]
数据都可以获取到，就是不能给select赋option值。
[其他解释]
append应该不行吧
[其他解释]

引用:

append应该不行吧

试过几种都不行
[其他解释]
$("#smallLineId").append(options);
这个不行要去掉你的是字符串的html脚本直接用$("#smallLineId").html(options); 就可以了
[其他解释]

var sel = $("#productName" + len + "").get(0);//得到select的DOM
 var options = "";
 for ( var i = 0; i < data.smallLinesList.length; i++) {
   var smallLine = data.smallLinesList[i];
   options = new Option(smallLine.name, "smallLine.id");
   sel.options.add(options);
}

[其他解释]

引用:

JavaScript code?12345678var sel = $("#productName" + len + "").get(0);//得到select的DOM var options = ""; for ( var i = 0; i < data.smallLinesList.length; i++) { var smallLine = data.small……

var sel = $("#smallLineId").get(0);//得到select的DOM
[其他解释]

引用:

JavaScript code?12345678var sel = $("#productName" + len + "").get(0);//得到select的DOM var options = ""; for ( var i = 0; i < data.smallLinesList.length; i++) { var smallLine = data.small……

没有那个add方法