org.hibernate.hql.ast.QuerySyntaxException: unexpected token解决方法
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我在利用hibernate的查询功能时总是出现org.hibernate.hql.ast.QuerySyntaxException: unexpected token异常，程序代码如下所示：
Employee employee = new Employee();
try{
Query query = session.createQuery( "form Employee as s where s.username = ? and s.password = ? ");
query.setString(0, username);
query.setString(1, password);
? }
tx.commit();
HibernateSessionFactory.closeSession();
}catch (HibernateException re) {
re.printStackTrace();
tx.rollback();
return false;
}
异常总是在 Query query = session.createQuery( "form Employee as s where s.username = ? and s.password = ? ");
处发生，请问高手这句话该怎么改正？非常盼望得到高手的指点，谢谢！
其中Employee类如下：
public class Employee implements java.io.Serializable {


private Integer id;
private String username;
private String password;
public Employee() {
}


// Property accessors

public Integer getId() {
return this.id;
}

public void setId(Integer id) {
this.id = id;
}

public String getUsername() {
return this.username;
}

public void setUsername(String username) {
this.username = username;
}

public String getPassword() {
return this.password;
}

public void setPassword(String password) {
this.password = password;
}
}


------解决方法--------------------

改为
Query query = session.createQuery( "form Employee as s where s.username = username and s.password = username ");

------解决方法--------------------
你的from都写成form了，看清楚！