帮忙找错
帮忙找错
#include <stdio.h>
#include <math.h>

int main()
{
float x;
x = log 90;
printf("%f\n", x);
return 0;
}

[解决办法]

#include <stdio.h>
#include <math.h>

int main()
{
  double x;
  x = log(90);
  printf("%lf\n", x);
  return 0;
}

[解决办法]
x = log 90; 改成 x = logl(90);
[解决办法]
float x;
x = log 90;
上面两句改为:
double x;
x = log(90)