为何第二个函数不被执行

为什么第二个函数不被执行
程序很简单就是打开然后登陆


using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Diagnostics;
using System.Runtime.InteropServices;
using System.Runtime.Serialization;

namespace ConsoleApplication2
{
    class Program
    {
        const int WM_SETTEXT = 0x000C;
        const int WM_LBUTTONDOWN = 0x0201;
        const int WM_LBUTTONUP = 0x0202;
        const int WM_CLOSE = 0x0010;
        public static string user = "账号";
        public static string pass = "123456";
        [DllImport("user32.dll")]
        public static extern IntPtr FindWindow(string lpClassName, string lpWindowName);

        [DllImport("User32.dll", EntryPoint = "SendMessage")]
        private static extern int SendMessage(IntPtr hWnd, int Msg, IntPtr wParam, string lParam);

        [DllImport("User32.dll ")]
        public static extern IntPtr FindWindowEx(IntPtr parent, IntPtr childe, string strclass, string FrmText);

        static void Main(string[] args)
        { 
            
            open();
            login();

           
           
        }

        private static void open()
        {
            Process pr = new Process();
            pr.StartInfo.FileName = @"D:\Program Files\11game\11Game.exe";
            

            pr.Start();
            
           
        
        }

        private static void login()
        {
            
          IntPtr hwnd = FindWindow("#32770", "11对战平台 - 1.0.4.3");
            IntPtr htextbox = FindWindowEx(hwnd, IntPtr.Zero, "ComboBox", null);
            IntPtr htextbox2 = FindWindowEx(hwnd, htextbox, "EDIT", null);//填上次获得的句柄，可以得到下一个的句柄 
 
            IntPtr hbutton = FindWindowEx(hwnd, IntPtr.Zero, "BUTTON", "登 录");


            SendMessage(htextbox, WM_SETTEXT, IntPtr.Zero, user);
            SendMessage(htextbox2, WM_SETTEXT, IntPtr.Zero, pass);
            SendMessage(hbutton, WM_LBUTTONDOWN, IntPtr.Zero, null);
            SendMessage(hbutton, WM_LBUTTONUP, IntPtr.Zero, null);
            
        }

    }
}

我想知道为什么我在login处下个断点然后调试执行可以成功直接运行程序就登陆不了了呢
[解决办法]
pr.Start();后面加
pr.WaitForExit();试试
[解决办法]
我想应该信息不对一般应该是 click 吧,你这个是 down + up
[解决办法]
因为11对战平台的启动需要时间的，而你在刚已启动后就马上找他的窗体，那么肯定找不到，你把
login函数中的第一行改为
while(true)
{
IntPtr hwnd = FindWindow("#32770", "11对战平台 - 1.0.4.3");
if(hwnd!=null)
break;
Thread.Sleep(100);
}
[解决办法]
FindWindow之前等待一下，找不到的话就循环等待再找几次。这个不是马上就能找到的。

为何第二个函数不被执行

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