java 获取客户端IP
在服务器端获得客户端ip怎么获得
我知道一个 方法request.getRemoteAddr()
可是我不知道 request 从哪里加进来
有没知道的

写在普通类里


有没谁知道啊
或者有没谁有其他方法啊！ 急啊！！！！！1
[解决办法]

/**
 * 
 */
package com.ccit.ejtg.util;

import javax.servlet.http.HttpServletRequest;

/**
 * @描述 获得IP4
 * @author XYY
 * @time 2010-3-22上午09:06:14
 * @version 1.0
 * @类名 IP4.java
 */
public class IP4 {

    public static String getIP4(HttpServletRequest request){
        String ip = request.getHeader("x-forwarded-for");
        if (ip == null 
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 ip.length() == 0 
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 "unknown".equalsIgnoreCase(ip)) {
            ip = request.getHeader("Proxy-Client-IP");
        }
        if (ip == null 
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 ip.length() == 0 
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 "unknown".equalsIgnoreCase(ip)) {
            ip = request.getHeader("WL-Proxy-Client-IP");
        }
        if (ip == null 
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 ip.length() == 0 
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 "unknown".equalsIgnoreCase(ip)) {
            ip = request.getRemoteAddr();
        }
        return ip;

    }
}

[解决办法]
楼上的说得漏了好几种情况,某些情况下还是获取的不正确,我下面的比较全几乎涵盖了所有的客户端形式,完全可以使用

public static String getIpAddr(HttpServletRequest request) {
String ip = request.getHeader("X-Forwarded-For");
if (ip == null
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ip.length() == 0
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"unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("Proxy-Client-IP");
}
if (ip == null
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ip.length() == 0
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"unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if (ip == null
------解决方案--------------------

ip.length() == 0
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"unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("HTTP_CLIENT_IP");
}
if (ip == null
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ip.length() == 0
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"unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("HTTP_X_FORWARDED_FOR");
}
if (ip == null
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ip.length() == 0
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"unknown".equalsIgnoreCase(ip)) {
ip = request.getRemoteAddr();
}
return ip;
}
[解决办法]

引用:

楼上的说得漏了好几种情况,某些情况下还是获取的不正确,我下面的比较全几乎涵盖了所有的客户端形式,完全可以使用

public static String getIpAddr(HttpServletRequest request) {
String ip = request.getHeader("X-Forwarded-For");
if (ip == null
[解决办法]
ip.length()……

学习了 谢谢 兄弟
[解决办法]

引用:

如果是jsp直接用request，如果是servlet，用HttpServletRequest request

request是从客户端来的