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INSTEAD OF 触发器的施用陷阱

发布时间: 2013-01-23 10:44:50 作者: rapoo

INSTEAD OF 触发器的使用陷阱
对于两张表以上关联起来的视图,Oracle是分不出来应该对哪个表进行更新
而INSTEAD OF 触发器实现了我们对视图DML的需求,显示的告诉告诉Oracle要更新哪个表
和其他类型触发器不同的是,INSTEAD OF 触发器实际上并不是由某个事件触发的

语法:

hr@ORCL> CREATE TABLE A (ID NUMBER(5),COL VARCHAR2(5));Table created.hr@ORCL> CREATE TABLE B (ID NUMBER(5),COL VARCHAR2(5));Table created.hr@ORCL> CREATE OR REPLACE VIEW V_AB AS  2      SELECT A.ID,A.COL AS COLA,B.COL AS COLB  3       FROM A,B  4      WHERE A.ID=B.ID  5      /View created.hr@ORCL> CREATE OR REPLACE TRIGGER TRG_V_AB  2      INSTEAD OF INSERT ON V_AB  3      FOR EACH ROW  4      BEGIN  5      INSERT INTO A(ID,COL)VALUES(:NEW.ID,:NEW.COLA);  6      INSERT INTO B(ID,COL)VALUES(:NEW.ID,:NEW.COLB);  7      END;  8      /Trigger created.hr@ORCL> SELECT TRIGGER_NAME,TRIGGER_TYPE FROM USER_TRIGGERS;TRIGGER_NAME                   TRIGGER_TYPE------------------------------ ----------------TRG_V_AB                       INSTEAD OF      hr@ORCL> INSERT INTO V_AB VALUES(1,'AA','BB');1 row created.hr@ORCL> COMMIT;Commit complete.hr@ORCL> select * from a;        ID COL---------- -----         1 AAhr@ORCL> select * from b;        ID COL---------- -----         1 BBhr@ORCL> CREATE OR REPLACE VIEW  V_AB AS  2      SELECT A.ID,B.COL AS COLA,A.COL AS COLB  3       FROM A,B  4      WHERE A.ID=B.ID  5      /View created.hr@ORCL> INSERT INTO V_AB VALUES(1,'AA','BB');INSERT INTO V_AB VALUES(1,'AA','BB')*ERROR at line 1:ORA-01779: cannot modify a column which maps to a non key-preserved tablehr@ORCL> SELECT TRIGGER_NAME,TRIGGER_TYPE FROM USER_TRIGGERS;no rows selected.

注释:
触发器,而且是行级触发器
:OLD:指更新以前的字段值
:new:指更新以后的字段值

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