读书人

求sql合计查询语句如上

发布时间: 2013-01-23 10:44:50 作者: rapoo

求sql合计查询语句,如下
表A (客户表)
ID,NAME(销售名), NUMBER
1, 'ZHANG', 1
2, 'LI' , 1
3, 'ZHANG' ,1
4, 'ZHANG' ,1
5, 'WANG' ,2

表B(合同表)
AID,NUM
2,1
3,2
效果如下:


name, 合同总数(A.ID=B.AID) 客户总数(A) 成单率
'ZHANG' 2 3 66.7%
'LI' 0 1 0
'WANG' 0 1 0 sql sql语句
[解决办法]
你的例子是不是有错啊?

----------------------------
-- Author :DBA_Huangzj()
-- Date :2013-01-15 20:21:54
-- Version:
-- Microsoft SQL Server 2008 R2 (SP1) - 10.50.2500.0 (Intel X86)
--Jun 17 2011 00:57:23
--Copyright (c) Microsoft Corporation
--Enterprise Edition on Windows NT 6.1 <X86> (Build 7601: Service Pack 1)
--
----------------------------
--> 测试数据:[表A]
if object_id('[表A]') is not null drop table [表A]
go
create table [表A]([ID] int,[NAME] varchar(5),[NUMBER] int)
insert [表A]
select 1,'ZHANG',1 union all
select 2,'LI',1 union all
select 3,'ZHANG',1 union all
select 4,'ZHANG',1 union all
select 5,'WANG',2
--> 测试数据:[表B]
if object_id('[表B]') is not null drop table [表B]
go
create table [表B]([AID] int,[NUM] int)
insert [表B]
select 2,1 union all
select 3,2
--------------开始查询--------------------------

select NAME,SUM(num) as [合同总数],COUNT(name) AS 客户总数,ISNULL(LEFT (CONVERT(VARCHAR(20),(SUM(num)*1./COUNT(name))),4),0)+'%' 成单率
from [表A] a LEFT JOIN [表B] b ON a.id=b.aid
GROUP BY name
----------------结果----------------------------
/*
NAME 合同总数 客户总数 成单率
----- ----------- ----------- ---------
LI 1 1 1.00%
WANG NULL 1 0%
ZHANG 2 3 0.66%
警告: 聚合或其他 SET 操作消除了 Null 值。

(3 行受影响)
*/

------解决方案--------------------


也可以创建个临时表:#表名,先group by 到临时表,再用联查语句 inner join(内连接),或左连接,2表联查。。
[解决办法]
要加上DISTINCT 排重。

USE test
GO


-->生成表A

if object_id('A') is not null
drop table A
Go
Create table A([ID] smallint,[NAME] nvarchar(9),[NUMBER] smallint)
Insert into A
Select 1,N'ZHANG',1
Union all Select 2,N'LI',1
Union all Select 3,N'ZHANG',1
Union all Select 4,N'ZHANG',1
Union all Select 5,N'WANG',2

-->生成表B

if object_id('B') is not null
drop table B
Go
Create table B([AID] smallint,[NUM] smallint)
Insert into B
Select 2,1
Union all Select 3,2

SELECT
name
,COUNT(b.NUM) AS [合同总数]
,COUNT(DISTINCT a.ID)AS [客户总数]
,LTRIM(CONVERT(NUMERIC(5,2),COUNT(b.NUM)*100.0/COUNT(DISTINCT a.ID)))+'%'AS [成单率]
FROM A
LEFT JOIN B AS b ON a.ID=b.AID
GROUP BY NAME
ORDER BY MIN(ID)

/*
name 合同总数 客户总数 成单率
--------- ----------- ----------- ------------------------------------------
ZHANG 1 3 33.33%
LI 1 1 100.00%
WANG 0 1 0.00%
*/

读书人网 >SQL Server

热点推荐