关于Select和Insert into的组合

SELECT TD.CUSTOMER_NO,TD.CARE_MONTH
FROM table
WHERE
CUSTOMER_NO = '1' AND CARE_MONTH = '20120821'

INSERT INTO
table(CUSTOMER_NO,CARE_MONTH,REGISTER,REGIST_TIME,UPDATER,UPDATE_TIME)
VALUES('1','20120821')

可否用一个SQL文
实现SELECT查不出来数据的话
就把这条数据查到数据库里
[解决办法]
insert into table1(CUSTOMER_NO,CARE_MONTH) --列的数量一定要和插入的值个数一样
(select *
from (select '1' id,'20120821' name ) a --这个是MSSQL中的写法
where not exists (SELECT 1
FROM table1
WHERE CUSTOMER_NO = '1'
AND CARE_MONTH = '20120821')
)

以上在MSSQL中测试是没问题的




[解决办法]

引用:

SQL code


SELECT TD.CUSTOMER_NO,TD.CARE_MONTH
FROM table
WHERE
CUSTOMER_NO = '1' AND CARE_MONTH = '20120821'




SQL code


INSERT INTO
table(CUSTOMER_NO,CARE_MONTH,REGISTER,REGIST_TIM……

oracle有个merge可以帮助你哦，参加我的blog：
http://blog.csdn.net/linwaterbin/article/details/7831747
[解决办法]
最好使用merge吧，效率比较高。
[解决办法]
是Oracle数据库还是mysql数据库呢？
[解决办法]
merge into security_clutter a
using (select '90001' ls_code,'PWD' act_code ,'test' act_name
from dual ) b
on (a.act_code = b.act_code)
when matched then
update set a.act_name = b.act_name
when not matched then
insert values (b.ls_code, b.act_code, b.act_name, '', '')
[解决办法]
楼上的when matched的应该可以跳过，直接when not matched...
[解决办法]
merge 可以解决！