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多个运算符重载产生no match

发布时间: 2013-01-28 11:49:56 作者: rapoo

多个运算符重载发生no match
代码基本与我上一个问题贴中相同:http://bbs.csdn.net/topics/390344120

不过我想多实现链表相加和赋值的功能,顺便把拷贝构造函数也自定义了一个:

template<class T>
class LinkedList {
public:
LinkedList();
LinkedList(const LinkedList<T> &list); //自定义的拷贝构造函数
~LinkedList();
void PushNode(T new_data);
void Delete(LinkedNode<T> *pnode);
bool CopyDelete(LinkedNode<T> *pnode);
bool CopyDeleteMiddle();
void Show();
int get_length();
void Clear();
LinkedList<T> operator+(LinkedList<T> &list); //重载加
LinkedList<T> &operator=(LinkedList<T> &list); //重载赋值
LinkedNode<T> *head;
LinkedNode<T> *tail;

private:
int length;
};


运算符重载函数的定义如下:
template <class T>
LinkedList<T>& LinkedList<T>::operator=(LinkedList<T> &list)
{
if (&list != this) {
Clear();
LinkedNode<T> *pnode = list.head;
while(pnode)
{
PushNode(pnode->data);
pnode = pnode->next;
}
}
return *this;
}

template <class T>
LinkedList<T> LinkedList<T>::operator+(LinkedList<T> &list)
{
int carry = 0;
LinkedList<T> sum_list;
LinkedNode<T> *pnode = list.head;
LinkedNode<T> *pnode_this = head;
if (!pnode || !pnode_this)
throw("Invalid list!");

T digit, digit_this, digit_sum;
while(pnode || pnode_this)
{
if (!pnode) {
digit = 0;
digit_this = pnode_this->data;
pnode_this = pnode_this->next;
} else if (!pnode_this) {
digit = pnode->data;
digit_this = 0;
pnode = pnode->next;
} else {
digit = pnode->data;
digit_this = pnode_this->data;
pnode = pnode->next;
pnode_this = pnode_this->next;
}
digit_sum = digit + digit_this + carry;
if (digit_sum >=10) {
digit_sum-=10;
carry = 1;
} else {
carry = 0;
}
sum_list.PushNode(digit_sum);

}


return sum_list;
}



main函数中,先实例化三个对象:
LinkedList<int> list1, list2, sum;
然后初始化前两个对象,执行:sum = list1+list2;

但编译时出现错误信息:
2_4.cc: In function ‘int main(int, char**)’:
2_4.cc:39:15: error: no match for ‘operator=’ in ‘sum = LinkedList<T>::operator+(LinkedList<T>&) [with T = int](((LinkedList<int>&)(& list2)))’
MySinglyLinkedList.h:171:16: note: candidate is: LinkedList<T>& LinkedList<T>::operator=(LinkedList<T>&) [with T = int]

不知我重载函数哪里写得有问题?
谢谢! list 运算符重载
[解决办法]
改成这样试试

LinkedList<T> operator+(LinkedList<T> const&list); //重载加
LinkedList<T> &operator=(LinkedList<T> const&list); //重载赋值

operator+ 以后生成的匿名对象是右值,不能绑定到 non-const lvalue referenc.

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