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ios里边的身份验证在webservice里面应

发布时间: 2013-03-04 17:22:12 作者: rapoo

ios里面的身份验证在webservice里面应该怎样写才能获取用户名密码
比如:
NSURL *url = [NSURL URLWithString:@"http://www.dreamingwish.com/"];
ASIHTTPRequest *request = [ASIHTTPRequest requestWithURL:url];
[request setUseKeychainPersistence:YES];
[request setUsername:@"username"];
[request setPassword:@"password"];

这里设置了用户名密码
webservise 在哪里获取

[解决办法]
webService里的代码我不知道怎么写。。
你看看你IOS里POST的代码吧

NSString *soapMessage =@"xxxxxxxxxx";

NSURL *url = [NSURL URLWithString:CMCC_ANTENNA_URL];
NSMutableURLRequest *theRequest = [NSMutableURLRequest requestWithURL:url];
NSString *msgLength = [NSString stringWithFormat:@"%d", [soapMessage length]];

[theRequest addValue: @"text/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
[theRequest addValue: FIND_ACTION forHTTPHeaderField:@"SOAPAction"];
[theRequest addValue: msgLength forHTTPHeaderField:@"Content-Length"];
[theRequest setHTTPMethod:@"POST"];
[theRequest setHTTPBody: [soapMessage dataUsingEncoding:NSUTF8StringEncoding]];

NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:theRequest delegate:self];

if( theConnection )
{
webData = [[NSMutableData data] retain];
}
else
{
NSLog(@"theConnection is NULL");
}

[解决办法]
呃。。。你不知道怎么组合request字符串吗?


NSString *str = [NSString stringWithFormat:
@"<?xml version=\"1.0\" encoding=\"utf-8\"?>\
<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\">\
<soap:Body>\
<Login xmlns=\"http://tempuri.org/\">\
<userName>%@</userName>\
<password>%@</password>\
</Login>\
</soap:Body>\
</soap:Envelope>", username, password];



[解决办法]
你这个是基于SOAP的WebService,iOS端要拼接SOAP请求格式才行,ASIHttpRequest只是以默认的Http请求格式发送请求,你服务器端当然收不到。
两种解决方案:
1、iOS端拼接SOAP请求格式通过进行请求
2、服务器端改成Restful的web service,你用.net的话可以用WCF Restful Template这个工程模板

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