急！求一条sql语句


求一条SQL语句，如图所示，目标是通过图一达到图二的效果（先判断name的值，如果有相同的值就只取一条数据，再把name值相同的id合并起来）
[解决办法]

SELECT  name ,
        [id] = STUFF(( SELECT   ',' + CONVERT(VARCHAR, id)
                       FROM     tb t
                       WHERE    name = tb.name
                     FOR
                       XML PATH('')
                     ), 1, 1, '')
FROM    tb
GROUP BY name

select [name],[id]=stuff(( select ',' +rtrim(id) from tb t2 where t1.[name]=t2.[name] for xml path('')), 1, 1, '')from tb t1
group by [name]

----------------------------
-- Author  :DBA_Huangzj()
-- Date    :2013-03-04 16:22:45
-- Version:
--      Microsoft SQL Server 2008 R2 (SP1) - 10.50.2500.0 (X64) 
--Jun 17 2011 00:54:03 
--Copyright (c) Microsoft Corporation
--Enterprise Edition (64-bit) on Windows NT 6.1 <X64> (Build 7601: Service Pack 1, v.721)
--
----------------------------
--> 测试数据：[huang]
if object_id('[huang]') is not null drop table [huang]
go 
create table [huang]([id] int,[NAME] varchar(6))
insert [huang]
select 1,'你好' union all
select 2,'你好' union all
select 3,'你好' union all
select 4,'我好' union all
select 5,'大家好'
--------------开始查询--------------------------

SELECT  a.name ,
        STUFF(( SELECT  ',' + CONVERT(VARCHAR(10),id)
                FROM    [huang] b
                WHERE   b.name = a.name
              FOR
                XML PATH('')
              ), 1, 1, '') 'id'
FROM    [huang] a
GROUP BY a.name 

 
 

----------------结果----------------------------
/* 
name   id
------ ----------------------------------------------------------------------------------------------------------------
大家好    5
你好     1,2,3
我好     4

(3 行受影响)
*/