杭电ACM多项式求和--》2011

#include <stdio.h>#include<iostream>using namespace std;int main(){    double sum=0;    int n,m;    scanf("%d",&n);    while(n--)    {        scanf("%d",&m);        for(int i=1;i<=m;i++)        {            if(i%2==0)            sum=sum-1.0/i;            else            sum=sum+1.0/i;        }        printf("%.2f ",sum);    }    return 0;}