杭电ACm求数列的和2009

#include <iostream>#include<stdio.h>#include <cmath>using namespace std;int main(){    double n,m,t=0;    while (cin>>n>>m&&n<10000&&m<1000)    {        t=0;        while (m--)        {            t=t+n;            n=sqrt(n);        }        printf("%.2f\n",t);    }return 0;}