再求高手指点下这个SQL怎么写请给具体SQL啊谢谢
col1 col2 col3
2012-01-01 1000 0001
2012-01-01 2222 0004
2012-01-01 3000 0001
2012-01-02 1000 0002
2012-01-02 2222 0004
2012-01-02 3000 0003
2012-01-03 1000 0002
2012-01-03 2222 0004
2012-01-03 3000 0004
2012-01-04 2222 0004
2012-01-04 3000 0003
2012-01-05 2222 0004
2012-01-05 3000 0003
其中col1是日期 col3是随便的数据 col1,col2,col3为联合主键
现在要查询col2在一个时间段内连续出现的数据如上的数据查询1到5号数据则结果为
col2
2222
3000


[解决办法]

引用:

引用:
用分析函数

给个具体的例子嘛

with machineTable
as
(
select '北京' cityid, 1 as statusid,'AAA' as machineID from dual
union
select '北京' , 0 ,'BBB' from dual
union
select '北京' , 0 ,'CCC' from dual
union
select '广州' , 1 ,'DDD' from dual
union
select '上海' , 0 ,'EEE' from dual
)
select mar.*
,decode(a,'0','0',decode(b,'0','0',100*ROUND(b/a,4)
[解决办法]
'%'))as c
from
(
select distinct cityid
,sum(case when 1=1 then 1 else 0 end) over(partition by cityid) a
,sum(case when 1=1 and statusid=1 then 1 else 0 end) over(partition by cityid) b
from machineTable
) mar
[解决办法]

[SYS@myoracle] SQL>with t1 as(
  2  select date'2012-01-01' col1, 1000 col2, '0001' col3 from dual union all
  3  select date'2012-01-01' col1, 2222 col2, '0004' col3 from dual union all
  4  select date'2012-01-01' col1, 3000 col2, '0001' col3 from dual union all
  5  select date'2012-01-02' col1, 1000 col2, '0002' col3 from dual union all
  6  select date'2012-01-02' col1, 2222 col2, '0004' col3 from dual union all
  7  select date'2012-01-02' col1, 3000 col2, '0003' col3 from dual union all
  8  select date'2012-01-03' col1, 1000 col2, '0002' col3 from dual union all
  9  select date'2012-01-03' col1, 2222 col2, '0004' col3 from dual union all
 10  select date'2012-01-03' col1, 3000 col2, '0004' col3 from dual union all 
 
 11  select date'2012-01-04' col1, 2222 col2, '0004' col3 from dual union all
 12  select date'2012-01-04' col1, 3000 col2, '0003' col3 from dual union all
 13  select date'2012-01-05' col1, 2222 col2, '0004' col3 from dual union all
 14  select date'2012-01-05' col1, 3000 col2, '0003' col3 from dual
 15  )select col2
 16     from (select row_number()over(partition by col2 order by col1) row_,
 17                  col1,col2,col3
 18             from t1
 19            where col1 between date'2012-01-01' and date'2012-01-05'
               --这个where条件是你需要根据你自己的需要改动的地方
 20           )
 21    group by col2,col1-row_
 22    having count(1) = date'2012-01-05'-date'2012-01-01' + 1
                        --这个条件也是你需要根据你自己的需要改动的地方
、
 23    order by col2;

      COL2
----------
      2222
      3000

[SYS@myoracle] SQL>

[解决办法]

with t as(
    select date'2012-01-01' col1, 1000 col2, '0001' col3 from dual union all
    select date'2012-01-01' col1, 2222 col2, '0004' col3 from dual union all
    select date'2012-01-01' col1, 3000 col2, '0001' col3 from dual union all
    select date'2012-01-02' col1, 1000 col2, '0002' col3 from dual union all
    select date'2012-01-02' col1, 2222 col2, '0004' col3 from dual union all
    select date'2012-01-02' col1, 3000 col2, '0003' col3 from dual union all
    select date'2012-01-03' col1, 1000 col2, '0002' col3 from dual union all
    select date'2012-01-03' col1, 2222 col2, '0004' col3 from dual union all
   select date'2012-01-03' col1, 3000 col2, '0004' col3 from dual union all
   select date'2012-01-04' col1, 2222 col2, '0004' col3 from dual union all
   select date'2012-01-04' col1, 3000 col2, '0003' col3 from dual union all
   select date'2012-01-05' col1, 2222 col2, '0004' col3 from dual union all
   select date'2012-01-05' col1, 3000 col2, '0003' col3 from dual 
 
   )

   SELECT col2 FROM 
   (
      SELECT (SELECT Count(DISTINCT col1) FROM t WHERE col1 between date'2012-01-01' and date'2012-01-05' )ncol1,
      Count(col2)ncol2,
      col2 
      FROM 
      (
        SELECT DISTINCT col1,col2 FROM t WHERE col1 between date'2012-01-01' and date'2012-01-05'
      )GROUP BY col2
   )WHERE ncol1=ncol2
  
   

[解决办法]
其实就是这样！
with t as(
select date'2012-01-01' col1, 1000 col2, '0001' col3 from dual union all
select date'2012-01-01' col1, 2222 col2, '0004' col3 from dual union all
select date'2012-01-01' col1, 3000 col2, '0001' col3 from dual union all
select date'2012-01-02' col1, 1000 col2, '0002' col3 from dual union all
select date'2012-01-02' col1, 2222 col2, '0004' col3 from dual union all
select date'2012-01-02' col1, 3000 col2, '0003' col3 from dual union all
select date'2012-01-03' col1, 1000 col2, '0002' col3 from dual union all
select date'2012-01-03' col1, 2222 col2, '0004' col3 from dual union all
select date'2012-01-03' col1, 3000 col2, '0004' col3 from dual union all
select date'2012-01-04' col1, 2222 col2, '0004' col3 from dual union all
select date'2012-01-04' col1, 3000 col2, '0003' col3 from dual union all
select date'2012-01-05' col1, 2222 col2, '0004' col3 from dual union all
select date'2012-01-05' col1, 3000 col2, '0003' col3 from dual
) SELECT col2 FROM t
WHERE col1 >=DATE'2012-01-01'AND col1<DATE'2012-01-06'
HAVING COUNT(col2)>=5
GROUP BY col2