error：“temp”的初始化操作由“case”标签跳过
我用VS 2008，编了一个关于class类的程序，其中用到了switch()语句，我写的代码如下：

if(number==1)
{
Complex_Number user_number;
switch(option)
{
case 1:
user_number.input(cin);
++user_number;
user_number.output(cout);
break;
case 2:
user_number.input(cin);
Complex_Number temp=user_number++;
temp.output(cout);
break;
case 3:
user_number.input(cin);
--user_number;
user_number.output(cout);
break;
case 4:
user_number.input(cin);
Complex_Number temp=user_number--;
temp.output(cout);
break;
case 5:
case 6:
case 7:
case 8:
cout<<"\n你的操作数不满足此运算！";
break;
}
当我编译时就会提示：error “temp”的初始化操作由“case”标签跳过（提示指着case 3那里），下面的从case 5到8都是这样，其中还有一个error “temp”: 重定义；多次初始化（提示指着case 4下面的Complex_Number temp那一行）。
求各位高手帮忙解答一下这个错误的根源在哪里？？
[解决办法]

if(number==1)
{
Complex_Number user_number;
Complex_Number temp;          //temp的定义放上来，不然会重定义
switch(option)
{
case 1:
user_number.input(cin);
++user_number;
user_number.output(cout);
break;
case 2:
user_number.input(cin);
temp=user_number++;
temp.output(cout);
break;
case 3:
user_number.input(cin);
--user_number;
user_number.output(cout);
break;
case 4:
user_number.input(cin);
temp=user_number--;
temp.output(cout);
break;
case 5:
case 6:
case 7:
case 8:
cout<<"\n你的操作数不满足此运算！";
break;
}

[解决办法]
switch case里面不能定义变量。
[解决办法]
+1

引用:

switch case里面不能定义变量。