大家看看这个输出是什么%#p，谢谢
printf("a_ptr=%#p,p_ptr=%#p\n",&a[4][2],&p[4][2]);

%#p是啥啊
[解决办法]
代表了在输出的地址前面加 0X
[解决办法]
# Specifies that the value is to be converted to an alternative form. For o conversion, it increases the
precision (if necessary) to force the first digit of the result to be zero. For x or X conversion speci-
fiers, a non-zero result shall have 0x (or 0X) prefixed to it. For a, A, e, E, f, F, g, and G conversion
specifiers, the result shall always contain a radix character, even if no digits follow the radix charac-
ter. Without this flag, a radix character appears in the result of these conversions only if a digit fol-
lows it. For g and G conversion specifiers, trailing zeros shall not be removed from the result as they
normally are. For other conversion specifiers, the behavior is undefined.


p The argument shall be a pointer to void. The value of the pointer is converted to a sequence of printable
characters, in an implementation-defined manner.
[解决办法]
是很少见的一个用法，放到程序里去试一下也就认识它了
输出了一个0X开头的8位16进制数 比如 0X0012FE7C
[解决办法]
%p是正确的
但是%#p是不对了。