Ctime函数 在ACM中的应用

• 咱们从一个题目开始进行导入
• http://acm.nbut.cn/Contest/view/id/38/problem/C.xhtml
  
• 
  
• [C] Minary Fights with Time
• 时间限制: 1000 ms　内存限制: 65535 K
• 问题描述
• Minary is busy now. As a result, she's fighting with time.
  To serialize every time point she marked, she decide to make every time point to an integer.
  
  You can imagine that 1970-01-01 00:00:00 GTM(Greenwich Mean Time) is the start. Give you an integer that indicates the total seconds from that time, you should output the time it stands for.
  
  
• 输入
• This problem contains several cases, input until EOF.
  Every case is an integer(-2^31 ~ 2^31-1) that indicates the total seconds from 1970-1-1 00:00:00 GTM.
  
• 输出
• For every case, you should output its time.
  
• 样例输入

• 0111111111113635924692147483647

• 样例输出

• 1970-01-01 00:00:002005-03-18 01:58:312013-03-18 07:41:092038-01-19 03:14:07

• 提示

• 无

• 来源

• Minary

  题意： 输入从1970-01-01 00:00:00 到现在的秒数 问现在的时间是什么

  #include<stdio.h>#include<string.h>#include<time.h>int main( void ){    struct tm *newtime;    char tmpbuf[128];    time_t lt1;time( <1 );//获得当前时间    newtime=localtime(<1);//转换成当地时间strftime( tmpbuf, 128, "Today is %A, day %d of %B in the year %Y.\n", newtime);    printf(tmpbuf);return 0;}